let X be non empty set ; :: thesis: for Y being set
for f, g being PartFunc of X,COMPLEX st Y c= dom (f + g) holds
( dom ((f | Y) + (g | Y)) = Y & (f + g) | Y = (f | Y) + (g | Y) )
let Y be set ; :: thesis: for f, g being PartFunc of X,COMPLEX st Y c= dom (f + g) holds
( dom ((f | Y) + (g | Y)) = Y & (f + g) | Y = (f | Y) + (g | Y) )
let f, g be PartFunc of X,COMPLEX ; :: thesis: ( Y c= dom (f + g) implies ( dom ((f | Y) + (g | Y)) = Y & (f + g) | Y = (f | Y) + (g | Y) ) )
assume A1:
Y c= dom (f + g)
; :: thesis: ( dom ((f | Y) + (g | Y)) = Y & (f + g) | Y = (f | Y) + (g | Y) )
then A0:
dom ((f + g) | Y) = Y
by RELAT_1:91;
A2:
dom (f + g) = (dom f) /\ (dom g)
by VALUED_1:def 1;
( dom (f | Y) = (dom f) /\ Y & dom (g | Y) = (dom g) /\ Y )
by RELAT_1:90;
then A3:
( dom (f | Y) = Y & dom (g | Y) = Y )
by A1, A2, XBOOLE_1:18, XBOOLE_1:28;
then A4:
dom ((f | Y) + (g | Y)) = Y /\ Y
by VALUED_1:def 1;
now let x be
set ;
:: thesis: ( x in dom ((f + g) | Y) implies ((f + g) | Y) . x = ((f | Y) + (g | Y)) . x )assume A5:
x in dom ((f + g) | Y)
;
:: thesis: ((f + g) | Y) . x = ((f | Y) + (g | Y)) . xhence ((f + g) | Y) . x =
(f + g) . x
by FUNCT_1:70
.=
(f . x) + (g . x)
by A0, A1, A5, VALUED_1:def 1
.=
((f | Y) . x) + (g . x)
by A0, A3, A5, FUNCT_1:70
.=
((f | Y) . x) + ((g | Y) . x)
by A0, A3, A5, FUNCT_1:70
.=
((f | Y) + (g | Y)) . x
by A0, A4, A5, VALUED_1:def 1
;
:: thesis: verum end;
hence
( dom ((f | Y) + (g | Y)) = Y & (f + g) | Y = (f | Y) + (g | Y) )
by A4, A1, FUNCT_1:9, RELAT_1:91; :: thesis: verum