hence
for A being set st A in S holds ( X \ A in S & ( for A, B being set st A in S & B in S holds A /\ B in S ) )
by A1, Def3; :: thesis: verum
end;
assume A4:
for A being set st A in S holds ( X \ A in S & ( for A, B being set st A in S & B in S holds A /\ B in S ) )
; :: thesis: S is Field_Subset of X then A5:
for A being set st A in S holds X \ A in S
;
for A, B being set st A in S & B in S holds A \/ B in S