let K be Field; :: thesis: for A, B being Matrix of K st the_rank_of A = the_rank_of (A ^^ B) & len A = len B holds
for N being finite without_zero Subset of NAT st N c= dom A & ( for i being Nat st i in N holds
Line A,i = (width A) |-> (0. K) ) holds
for i being Nat st i in N holds
Line B,i = (width B) |-> (0. K)
let A, B be Matrix of K; :: thesis: ( the_rank_of A = the_rank_of (A ^^ B) & len A = len B implies for N being finite without_zero Subset of NAT st N c= dom A & ( for i being Nat st i in N holds
Line A,i = (width A) |-> (0. K) ) holds
for i being Nat st i in N holds
Line B,i = (width B) |-> (0. K) )
assume A1:
( the_rank_of A = the_rank_of (A ^^ B) & len A = len B )
; :: thesis: for N being finite without_zero Subset of NAT st N c= dom A & ( for i being Nat st i in N holds
Line A,i = (width A) |-> (0. K) ) holds
for i being Nat st i in N holds
Line B,i = (width B) |-> (0. K)
reconsider A' = A as Matrix of len A, width A,K by MATRIX_2:7;
reconsider B' = B as Matrix of len A, width B,K by A1, MATRIX_2:7;
set AB = A' ^^ B';
let N be finite without_zero Subset of NAT ; :: thesis: ( N c= dom A & ( for i being Nat st i in N holds
Line A,i = (width A) |-> (0. K) ) implies for i being Nat st i in N holds
Line B,i = (width B) |-> (0. K) )
assume that
A2:
N c= dom A
and
A3:
for i being Nat st i in N holds
Line A,i = (width A) |-> (0. K)
; :: thesis: for i being Nat st i in N holds
Line B,i = (width B) |-> (0. K)
let i be Nat; :: thesis: ( i in N implies Line B,i = (width B) |-> (0. K) )
assume A4:
i in N
; :: thesis: Line B,i = (width B) |-> (0. K)
assume
Line B,i <> (width B) |-> (0. K)
; :: thesis: contradiction
then consider j being Nat such that
A5:
( j in Seg (width B) & (Line B,i) . j <> ((width B) |-> (0. K)) . j )
by FINSEQ_2:139;
A6:
dom A = Seg (len A)
by FINSEQ_1:def 3;
len A <> 0
by A2, A4, FINSEQ_1:4, FINSEQ_1:def 3;
then
len A > 0
;
then A7:
( width (A' ^^ B') = (width A) + (width B) & dom (A' ^^ B') = Seg (len (A' ^^ B')) & len (A' ^^ B') = len A & Indices (A' ^^ B') = [:(Seg (len A)),(Seg ((width A) + (width B))):] )
by FINSEQ_1:def 3, MATRIX_1:24;
then A8:
j + (width A) in Seg (width (A' ^^ B'))
by A5, FINSEQ_1:81;
A9:
( len (Line B',i) = width B' & len (Line A',i) = width A' )
by MATRIX_1:def 8;
then A10:
( 1 <= j & j <= len (Line B',i) )
by A5, FINSEQ_1:3;
(A' ^^ B') * i,(j + (width A)) =
(Line (A' ^^ B'),i) . (j + (width A))
by A8, MATRIX_1:def 8
.=
((Line A',i) ^ (Line B',i)) . (j + (width A))
by A2, A4, A6, Th15
.=
(Line B',i) . j
by A9, A10, FINSEQ_1:86
;
then A11:
(A' ^^ B') * i,(j + (width A)) <> 0. K
by A5, FINSEQ_2:71;
consider P, Q being finite without_zero Subset of NAT such that
A12:
( [:P,Q:] c= Indices A' & card P = card Q )
and
A13:
card P = the_rank_of A'
and
A14:
Det (EqSegm A',P,Q) <> 0. K
by MATRIX13:def 4;
A15:
Segm (A' ^^ B'),(Seg (len A)),(Seg (width A)) = A
by Th19;
( P = {} iff Q = {} )
by A12;
then consider P2, Q2 being finite without_zero Subset of NAT such that
A16:
( P2 c= Seg (len A) & Q2 c= Seg (width A) )
and
A17:
( P2 = (Sgm (Seg (len A))) .: P & Q2 = (Sgm (Seg (width A))) .: Q )
and
( card P2 = card P & card Q2 = card Q )
and
A18:
Segm A,P,Q = Segm (A' ^^ B'),P2,Q2
by A12, A15, MATRIX13:57;
width A <= width (A' ^^ B')
by A7, NAT_1:11;
then A19:
Seg (width A) c= Seg (width (A' ^^ B'))
by FINSEQ_1:7;
then A20:
[:P2,(Seg (width A)):] c= Indices (A' ^^ B')
by A16, A7, ZFMISC_1:119;
not i in P2
proof
assume A21:
i in P2
;
:: thesis: contradiction
A22:
Sgm (Seg (len A)) =
idseq (len A)
by FINSEQ_3:54
.=
id (Seg (len A))
;
A23:
(
P c= Seg (len A) &
Q c= Seg (width A) )
by A12, MATRIX13:67;
then A24:
i in P
by A21, A17, A22, FUNCT_1:162;
A25:
(
dom (Sgm P) = Seg (card P) &
rng (Sgm P) = P &
dom (Sgm Q) = Seg (card Q) &
rng (Sgm Q) = Q )
by A23, FINSEQ_1:def 13, FINSEQ_3:45;
then consider x being
set such that A26:
(
x in dom (Sgm P) &
(Sgm P) . x = i )
by A24, FUNCT_1:def 5;
reconsider x =
x as
Element of
NAT by A26;
A27:
dom (Line A,i) = Seg (width A)
by FINSEQ_2:144;
Line A,
i =
(width A) |-> (0. K)
by A3, A4
.=
(0. K) * (Line A,i)
by FVSUM_1:71
;
then
(
Line (Segm A,P,Q),
x = ((0. K) * (Line A,i)) * (Sgm Q) &
Line (Segm A,P,Q),
x = (Line A,i) * (Sgm Q) )
by A23, A25, A26, MATRIX13:47;
then
(
Line (Segm A,P,Q),
x = (0. K) * (Line (Segm A,P,Q),x) &
Segm A,
P,
Q = EqSegm A,
P,
Q )
by A12, A23, A25, A27, MATRIX13:87, MATRIX13:def 3;
then (0. K) * (Det (EqSegm A,P,Q)) =
Det (RLine (EqSegm A,P,Q),x,(Line (EqSegm A,P,Q),x))
by A25, A26, MATRIX11:35
.=
Det (EqSegm A,P,Q)
by MATRIX11:30
;
hence
contradiction
by A14, VECTSP_1:36;
:: thesis: verum
end;
then A28:
i in (dom (A' ^^ B')) \ P2
by A2, A4, A6, A7, XBOOLE_0:def 5;
j >= 1
by A5, FINSEQ_1:3;
then
j + (width A) >= 1 + (width A)
by XREAL_1:8;
then
j + (width A) > width A
by NAT_1:13;
then
not j + (width A) in Q2
by A16, FINSEQ_1:3;
then A29:
j + (width A) in (Seg (width (A' ^^ B'))) \ Q2
by A8, XBOOLE_0:def 5;
A30:
( card (Seg (len A)) = len A & card (Seg (width A)) = width A )
by FINSEQ_1:78;
A31: (Sgm (Seg (len A))) . i =
(idseq (len A)) . i
by FINSEQ_3:54
.=
i
by A6, A2, A4, FINSEQ_2:57
;
(card (Seg (width A))) |-> (0. K) =
Line A,i
by A3, A4, A30
.=
(Line (A' ^^ B'),i) * (Sgm (Seg (width A)))
by A31, A30, A19, A15, A2, A4, A6, MATRIX13:47
;
then A32:
card P > the_rank_of (Segm (A' ^^ B'),P2,Q2)
by A1, A16, Th10, A20, A28, A29, A11, A13;
Segm (A' ^^ B'),P2,Q2 = EqSegm A,P,Q
by A12, A18, MATRIX13:def 3;
hence
contradiction
by A32, A14, MATRIX13:83; :: thesis: verum