assume
x in{ d where d is Element of L : ( d in D & d [= x ) }
; :: thesis: contradiction then
ex x' being Element of L st ( x' = x & x' in D & x' [= x )
; hence
contradiction
by A3; :: thesis: verum
end;
for u being set st u in{ d where d is Element of L : ( d in D & d [= x ) } holds u in{ d where d is Element of L : ( d [= x & d <> x ) }