set A = KurExSet ;
assume
{(Int KurExSet ),(Int (Cl KurExSet )),(Int (Cl (Int KurExSet ))),(Cl KurExSet ),(Cl (Int KurExSet )),(Cl (Int (Cl KurExSet )))} meets {KurExSet }
; :: thesis: contradiction
then A1:
KurExSet in {(Int KurExSet ),(Int (Cl KurExSet )),(Int (Cl (Int KurExSet ))),(Cl KurExSet ),(Cl (Int KurExSet )),(Cl (Int (Cl KurExSet )))}
by ZFMISC_1:56;