let P be Subset of (TOP-REAL 2); :: thesis: for p1, p2, q1, q2 being Point of (TOP-REAL 2) st P is_an_arc_of p1,p2 & q1 in P & q2 in P & q1 <> q2 & not ( LE q1,q2,P,p1,p2 & not LE q2,q1,P,p1,p2 ) holds
( LE q2,q1,P,p1,p2 & not LE q1,q2,P,p1,p2 )
let p1, p2, q1, q2 be Point of (TOP-REAL 2); :: thesis: ( P is_an_arc_of p1,p2 & q1 in P & q2 in P & q1 <> q2 & not ( LE q1,q2,P,p1,p2 & not LE q2,q1,P,p1,p2 ) implies ( LE q2,q1,P,p1,p2 & not LE q1,q2,P,p1,p2 ) )
assume A1:
( P is_an_arc_of p1,p2 & q1 in P & q2 in P & q1 <> q2 )
; :: thesis: ( ( LE q1,q2,P,p1,p2 & not LE q2,q1,P,p1,p2 ) or ( LE q2,q1,P,p1,p2 & not LE q1,q2,P,p1,p2 ) )
then reconsider P = P as non empty Subset of (TOP-REAL 2) ;
( ( LE q1,q2,P,p1,p2 & not LE q2,q1,P,p1,p2 ) or ( LE q2,q1,P,p1,p2 & not LE q1,q2,P,p1,p2 ) )
proof
assume A2:
(
LE q1,
q2,
P,
p1,
p2 iff
LE q2,
q1,
P,
p1,
p2 )
;
:: thesis: contradiction
consider f being
Function of
I[01] ,
((TOP-REAL 2) | P) such that A3:
(
f is
being_homeomorphism &
f . 0 = p1 &
f . 1
= p2 )
by A1, TOPREAL1:def 2;
A4:
rng f =
[#] ((TOP-REAL 2) | P)
by A3, TOPS_2:def 5
.=
P
by PRE_TOPC:def 10
;
then consider x being
set such that A5:
(
x in dom f &
q1 = f . x )
by A1, FUNCT_1:def 5;
consider y being
set such that A6:
(
y in dom f &
q2 = f . y )
by A1, A4, FUNCT_1:def 5;
dom f =
[#] I[01]
by A3, TOPS_2:def 5
.=
[.0 ,1.]
by BORSUK_1:83
;
then reconsider s1 =
x,
s2 =
y as
Real by A5, A6;
A7:
(
f . s1 = q1 &
0 <= s1 &
s1 <= 1 &
f . s2 = q2 &
0 <= s2 &
s2 <= 1 )
by A5, A6, BORSUK_1:86;
end;
hence
( ( LE q1,q2,P,p1,p2 & not LE q2,q1,P,p1,p2 ) or ( LE q2,q1,P,p1,p2 & not LE q1,q2,P,p1,p2 ) )
; :: thesis: verum