let C be Simple_closed_curve; :: thesis: for n being Element of NAT st n is_sufficiently_large_for C holds
C misses RightComp (Span C,n)
let n be Element of NAT ; :: thesis: ( n is_sufficiently_large_for C implies C misses RightComp (Span C,n) )
assume A1:
n is_sufficiently_large_for C
; :: thesis: C misses RightComp (Span C,n)
set f = Span C,n;
A2:
C misses L~ (Span C,n)
by A1, Th9;
A3:
C meets LeftComp (Span C,n)
by A1, Th10;
assume A4:
C meets RightComp (Span C,n)
; :: thesis: contradiction
RightComp (Span C,n) is_a_component_of (L~ (Span C,n)) `
by GOBOARD9:def 2;
then consider L being Subset of ((TOP-REAL 2) | ((L~ (Span C,n)) ` )) such that
A5:
L = RightComp (Span C,n)
and
A6:
L is_a_component_of (TOP-REAL 2) | ((L~ (Span C,n)) ` )
by CONNSP_1:def 6;
LeftComp (Span C,n) is_a_component_of (L~ (Span C,n)) `
by GOBOARD9:def 1;
then consider R being Subset of ((TOP-REAL 2) | ((L~ (Span C,n)) ` )) such that
A7:
R = LeftComp (Span C,n)
and
A8:
R is_a_component_of (TOP-REAL 2) | ((L~ (Span C,n)) ` )
by CONNSP_1:def 6;
C c= the carrier of ((TOP-REAL 2) | ((L~ (Span C,n)) ` ))
then reconsider C1 = C as Subset of ((TOP-REAL 2) | ((L~ (Span C,n)) ` )) ;
C1 is connected
by CONNSP_1:24;
hence
contradiction
by A3, A4, A5, A6, A7, A8, JORDAN2C:100, SPRECT_4:7; :: thesis: verum