let A be closed-interval Subset of REAL ; :: thesis: for Z being open Subset of REAL st A c= Z & ( for x being Real st x in Z holds
x > 0 ) & dom ln = Z & Z = dom ((id Z) ^ ) & ((id Z) ^ ) | A is continuous holds
integral ((id Z) ^ ),A = (ln . (upper_bound A)) - (ln . (lower_bound A))
let Z be open Subset of REAL ; :: thesis: ( A c= Z & ( for x being Real st x in Z holds
x > 0 ) & dom ln = Z & Z = dom ((id Z) ^ ) & ((id Z) ^ ) | A is continuous implies integral ((id Z) ^ ),A = (ln . (upper_bound A)) - (ln . (lower_bound A)) )
set f2 = (id Z) ^ ;
assume A1:
( A c= Z & ( for x being Real st x in Z holds
x > 0 ) & dom ln = Z & Z = dom ((id Z) ^ ) & ((id Z) ^ ) | A is continuous )
; :: thesis: integral ((id Z) ^ ),A = (ln . (upper_bound A)) - (ln . (lower_bound A))
then A2:
( (id Z) ^ is_integrable_on A & ((id Z) ^ ) | A is bounded )
by INTEGRA5:10, INTEGRA5:11;
A3:
ln is_differentiable_on Z
by A1, FDIFF_5:19;
A4:
for x being Real st x in dom (ln `| Z) holds
(ln `| Z) . x = ((id Z) ^ ) . x
dom (ln `| Z) = dom ((id Z) ^ )
by A1, A3, FDIFF_1:def 8;
then
ln `| Z = (id Z) ^
by A4, PARTFUN1:34;
hence
integral ((id Z) ^ ),A = (ln . (upper_bound A)) - (ln . (lower_bound A))
by A1, A2, A3, INTEGRA5:13; :: thesis: verum