let a be Real; :: thesis: for A being closed-interval Subset of REAL
for f, f2 being PartFunc of REAL ,REAL
for Z being open Subset of REAL st A c= Z & ( for x being Real st x in Z holds
( f . x = x - a & f . x > 0 ) ) & dom (ln * f) = Z & dom (ln * f) = dom f2 & ( for x being Real st x in Z holds
f2 . x = 1 / (x - a) ) & f2 | A is continuous holds
integral f2,A = ((ln * f) . (upper_bound A)) - ((ln * f) . (lower_bound A))
let A be closed-interval Subset of REAL ; :: thesis: for f, f2 being PartFunc of REAL ,REAL
for Z being open Subset of REAL st A c= Z & ( for x being Real st x in Z holds
( f . x = x - a & f . x > 0 ) ) & dom (ln * f) = Z & dom (ln * f) = dom f2 & ( for x being Real st x in Z holds
f2 . x = 1 / (x - a) ) & f2 | A is continuous holds
integral f2,A = ((ln * f) . (upper_bound A)) - ((ln * f) . (lower_bound A))
let f, f2 be PartFunc of REAL ,REAL ; :: thesis: for Z being open Subset of REAL st A c= Z & ( for x being Real st x in Z holds
( f . x = x - a & f . x > 0 ) ) & dom (ln * f) = Z & dom (ln * f) = dom f2 & ( for x being Real st x in Z holds
f2 . x = 1 / (x - a) ) & f2 | A is continuous holds
integral f2,A = ((ln * f) . (upper_bound A)) - ((ln * f) . (lower_bound A))
let Z be open Subset of REAL ; :: thesis: ( A c= Z & ( for x being Real st x in Z holds
( f . x = x - a & f . x > 0 ) ) & dom (ln * f) = Z & dom (ln * f) = dom f2 & ( for x being Real st x in Z holds
f2 . x = 1 / (x - a) ) & f2 | A is continuous implies integral f2,A = ((ln * f) . (upper_bound A)) - ((ln * f) . (lower_bound A)) )
assume A1:
( A c= Z & ( for x being Real st x in Z holds
( f . x = x - a & f . x > 0 ) ) & dom (ln * f) = Z & dom (ln * f) = dom f2 & ( for x being Real st x in Z holds
f2 . x = 1 / (x - a) ) & f2 | A is continuous )
; :: thesis: integral f2,A = ((ln * f) . (upper_bound A)) - ((ln * f) . (lower_bound A))
then A2:
( f2 is_integrable_on A & f2 | A is bounded )
by INTEGRA5:10, INTEGRA5:11;
A3:
ln * f is_differentiable_on Z
by A1, FDIFF_4:2;
A4:
for x being Real st x in dom ((ln * f) `| Z) holds
((ln * f) `| Z) . x = f2 . x
dom ((ln * f) `| Z) = dom f2
by A1, A3, FDIFF_1:def 8;
then
(ln * f) `| Z = f2
by A4, PARTFUN1:34;
hence
integral f2,A = ((ln * f) . (upper_bound A)) - ((ln * f) . (lower_bound A))
by A1, A2, A3, INTEGRA5:13; :: thesis: verum