let A be closed-interval Subset of REAL ; :: thesis: for Z being open Subset of REAL st A c= Z holds
integral ((- cos ) + ((id Z) (#) sin )),A = (((- (id Z)) (#) cos ) . (upper_bound A)) - (((- (id Z)) (#) cos ) . (lower_bound A))
let Z be open Subset of REAL ; :: thesis: ( A c= Z implies integral ((- cos ) + ((id Z) (#) sin )),A = (((- (id Z)) (#) cos ) . (upper_bound A)) - (((- (id Z)) (#) cos ) . (lower_bound A)) )
assume A:
A c= Z
; :: thesis: integral ((- cos ) + ((id Z) (#) sin )),A = (((- (id Z)) (#) cos ) . (upper_bound A)) - (((- (id Z)) (#) cos ) . (lower_bound A))
A1:
dom ((- (id Z)) (#) cos ) = Z
A2:
Z = dom ((- cos ) + ((id Z) (#) sin ))
Z = (dom (- cos )) /\ (dom ((id Z) (#) sin ))
by A2, VALUED_1:def 1;
then D:
( Z c= dom (- cos ) & Z c= dom ((id Z) (#) sin ) )
by XBOOLE_1:18;
then
( Z c= dom (- cos ) & Z c= (dom (id Z)) /\ (dom sin ) )
by VALUED_1:def 4;
then AA:
( Z c= dom (- cos ) & Z c= dom (id Z) & Z c= dom sin )
by XBOOLE_1:18;
AB:
for x being Real st x in Z holds
(id Z) . x = (1 * x) + 0
by FUNCT_1:35;
B:
for x being Real st x in Z holds
((- cos ) + ((id Z) (#) sin )) . x = (- (cos . x)) + (x * (sin . x))
C1:
id Z is_differentiable_on Z
by AA, AB, FDIFF_1:31;
sin is_differentiable_on Z
by FDIFF_1:34, SIN_COS:73;
then C2:
(id Z) (#) sin is_differentiable_on Z
by D, C1, FDIFF_1:29;
- cos is_differentiable_on Z
by FDIFF_1:34, INTEGRA8:26;
then
((- cos ) + ((id Z) (#) sin )) | Z is continuous
by A2, C2, FDIFF_1:26, FDIFF_1:33;
then
((- cos ) + ((id Z) (#) sin )) | A is continuous
by A, FCONT_1:17;
then A3:
( (- cos ) + ((id Z) (#) sin ) is_integrable_on A & ((- cos ) + ((id Z) (#) sin )) | A is bounded )
by A, A2, INTEGRA5:10, INTEGRA5:11;
A4:
(- (id Z)) (#) cos is_differentiable_on Z
by A1, FDIFF_4:44;
A5:
for x being Real st x in dom (((- (id Z)) (#) cos ) `| Z) holds
(((- (id Z)) (#) cos ) `| Z) . x = ((- cos ) + ((id Z) (#) sin )) . x
dom (((- (id Z)) (#) cos ) `| Z) = dom ((- cos ) + ((id Z) (#) sin ))
by A2, A4, FDIFF_1:def 8;
then
((- (id Z)) (#) cos ) `| Z = (- cos ) + ((id Z) (#) sin )
by A5, PARTFUN1:34;
hence
integral ((- cos ) + ((id Z) (#) sin )),A = (((- (id Z)) (#) cos ) . (upper_bound A)) - (((- (id Z)) (#) cos ) . (lower_bound A))
by A, A1, A3, FDIFF_4:44, INTEGRA5:13; :: thesis: verum