let f be PartFunc of REAL ,REAL ; :: thesis: for A, B, C being closed-interval Subset of REAL
for X being set st A c= X & f is_differentiable_on X & (f `| X) | A is continuous & inf A = inf B & sup B = inf C & sup C = sup A holds
( B c= A & C c= A & integral (f `| X),A = (integral (f `| X),B) + (integral (f `| X),C) )
let A, B, C be closed-interval Subset of REAL ; :: thesis: for X being set st A c= X & f is_differentiable_on X & (f `| X) | A is continuous & inf A = inf B & sup B = inf C & sup C = sup A holds
( B c= A & C c= A & integral (f `| X),A = (integral (f `| X),B) + (integral (f `| X),C) )
let X be set ; :: thesis: ( A c= X & f is_differentiable_on X & (f `| X) | A is continuous & inf A = inf B & sup B = inf C & sup C = sup A implies ( B c= A & C c= A & integral (f `| X),A = (integral (f `| X),B) + (integral (f `| X),C) ) )
assume that
A1:
A c= X
and
A2:
f is_differentiable_on X
and
A3:
(f `| X) | A is continuous
and
A4:
inf A = inf B
and
A5:
sup B = inf C
and
A6:
sup C = sup A
; :: thesis: ( B c= A & C c= A & integral (f `| X),A = (integral (f `| X),B) + (integral (f `| X),C) )
X:
A c= dom (f `| X)
by A2, A1, FDIFF_1:def 8;
consider x being Real such that
A7:
x in B
by SUBSET_1:10;
( inf B <= x & x <= sup B )
by A7, INTEGRA2:1;
then A8:
inf B <= sup B
by XXREAL_0:2;
consider x being Real such that
A9:
x in C
by SUBSET_1:10;
( inf C <= x & x <= sup C )
by A9, INTEGRA2:1;
then A10:
inf C <= sup C
by XXREAL_0:2;
for x being set st x in B holds
x in A
hence A12:
B c= A
by TARSKI:def 3; :: thesis: ( C c= A & integral (f `| X),A = (integral (f `| X),B) + (integral (f `| X),C) )
for x being set st x in C holds
x in A
hence A14:
C c= A
by TARSKI:def 3; :: thesis: integral (f `| X),A = (integral (f `| X),B) + (integral (f `| X),C)
then B14:
( B c= dom (f `| X) & C c= dom (f `| X) )
by A12, X, XBOOLE_1:1;
( (f `| X) | A is continuous & (f `| X) | B is continuous & (f `| X) | C is continuous )
by A3, A12, A14, FCONT_1:17;
then A15:
( f `| X is_integrable_on A & f `| X is_integrable_on B & f `| X is_integrable_on C )
by Th11, X, B14;
A16:
(f `| X) | A is bounded
by A3, Th10, X;
then
( (f `| X) | B is bounded & (f `| X) | C is bounded )
by A12, A14, RFUNCT_1:91;
then
( integral (f `| X),A = (f . (sup A)) - (f . (inf A)) & integral (f `| X),B = (f . (sup B)) - (f . (inf B)) & integral (f `| X),C = (f . (sup C)) - (f . (inf C)) )
by A1, A2, A12, A14, A15, A16, Th13, XBOOLE_1:1;
hence
integral (f `| X),A = (integral (f `| X),B) + (integral (f `| X),C)
by A4, A5, A6; :: thesis: verum