let A be closed-interval Subset of REAL ; :: thesis: for Z being open Subset of REAL
for f, f1, f2 being PartFunc of REAL ,REAL st A c= Z & Z c= ].(- 1),1.[ & f = f1 - f2 & f2 = #Z 2 & ( for x being Real st x in Z holds
( f1 . x = 1 & f . x > 0 & x <> 0 ) ) & dom arcsin = Z & Z c= dom (((id Z) (#) arcsin ) + ((#R (1 / 2)) * f)) holds
integral arcsin ,A = ((((id Z) (#) arcsin ) + ((#R (1 / 2)) * f)) . (sup A)) - ((((id Z) (#) arcsin ) + ((#R (1 / 2)) * f)) . (inf A))
let Z be open Subset of REAL ; :: thesis: for f, f1, f2 being PartFunc of REAL ,REAL st A c= Z & Z c= ].(- 1),1.[ & f = f1 - f2 & f2 = #Z 2 & ( for x being Real st x in Z holds
( f1 . x = 1 & f . x > 0 & x <> 0 ) ) & dom arcsin = Z & Z c= dom (((id Z) (#) arcsin ) + ((#R (1 / 2)) * f)) holds
integral arcsin ,A = ((((id Z) (#) arcsin ) + ((#R (1 / 2)) * f)) . (sup A)) - ((((id Z) (#) arcsin ) + ((#R (1 / 2)) * f)) . (inf A))
let f, f1, f2 be PartFunc of REAL ,REAL ; :: thesis: ( A c= Z & Z c= ].(- 1),1.[ & f = f1 - f2 & f2 = #Z 2 & ( for x being Real st x in Z holds
( f1 . x = 1 & f . x > 0 & x <> 0 ) ) & dom arcsin = Z & Z c= dom (((id Z) (#) arcsin ) + ((#R (1 / 2)) * f)) implies integral arcsin ,A = ((((id Z) (#) arcsin ) + ((#R (1 / 2)) * f)) . (sup A)) - ((((id Z) (#) arcsin ) + ((#R (1 / 2)) * f)) . (inf A)) )
assume A1:
( A c= Z & Z c= ].(- 1),1.[ & f = f1 - f2 & f2 = #Z 2 & ( for x being Real st x in Z holds
( f1 . x = 1 & f . x > 0 & x <> 0 ) ) & dom arcsin = Z & Z c= dom (((id Z) (#) arcsin ) + ((#R (1 / 2)) * f)) )
; :: thesis: integral arcsin ,A = ((((id Z) (#) arcsin ) + ((#R (1 / 2)) * f)) . (sup A)) - ((((id Z) (#) arcsin ) + ((#R (1 / 2)) * f)) . (inf A))
arcsin | A is continuous
;
then A2:
( arcsin is_integrable_on A & arcsin | A is bounded )
by A1, INTEGRA5:10, INTEGRA5:11;
A3:
((id Z) (#) arcsin ) + ((#R (1 / 2)) * f) is_differentiable_on Z
by A1, FDIFF_7:23;
A4:
for x being Real st x in dom ((((id Z) (#) arcsin ) + ((#R (1 / 2)) * f)) `| Z) holds
((((id Z) (#) arcsin ) + ((#R (1 / 2)) * f)) `| Z) . x = arcsin . x
dom ((((id Z) (#) arcsin ) + ((#R (1 / 2)) * f)) `| Z) = dom arcsin
by A1, A3, FDIFF_1:def 8;
then
(((id Z) (#) arcsin ) + ((#R (1 / 2)) * f)) `| Z = arcsin
by A4, PARTFUN1:34;
hence
integral arcsin ,A = ((((id Z) (#) arcsin ) + ((#R (1 / 2)) * f)) . (sup A)) - ((((id Z) (#) arcsin ) + ((#R (1 / 2)) * f)) . (inf A))
by A1, A2, A3, INTEGRA5:13; :: thesis: verum