let A be set ; :: thesis: for a being Element of DISJOINT_PAIRS A
for K being Element of Normal_forms_on A st K ^ {a} = {} holds
ex b being Element of DISJOINT_PAIRS A st
( b in - K & b c= a )
let a be Element of DISJOINT_PAIRS A; :: thesis: for K being Element of Normal_forms_on A st K ^ {a} = {} holds
ex b being Element of DISJOINT_PAIRS A st
( b in - K & b c= a )
let K be Element of Normal_forms_on A; :: thesis: ( K ^ {a} = {} implies ex b being Element of DISJOINT_PAIRS A st
( b in - K & b c= a ) )
assume A1:
K ^ {a} = {}
; :: thesis: ex b being Element of DISJOINT_PAIRS A st
( b in - K & b c= a )
now per cases
( not A is empty or A is empty )
;
suppose A14:
A is
empty
;
:: thesis: ex b being Element of DISJOINT_PAIRS A st
( b in - K & b c= a )then A15:
a = [{} ,{} ]
by Th20;
take b =
a;
:: thesis: ( b in - K & b c= a )reconsider Z =
{[{} ,{} ]} as
Element of
Normal_forms_on {} by Th22;
mi (Z ^ Z) <> {}
by Th7;
then
K <> {[{} ,{} ]}
by A1, A14, A15, NORMFORM:64, XBOOLE_1:3;
then
K = {}
by A14, Lm4, TARSKI:def 2;
then
- K = {[{} ,{} ]}
by Th18;
hence
b in - K
by A15, TARSKI:def 1;
:: thesis: b c= athus
b c= a
;
:: thesis: verum end; end; end;
hence
ex b being Element of DISJOINT_PAIRS A st
( b in - K & b c= a )
; :: thesis: verum