let G be Group; :: thesis: for H2, H1 being Subgroup of G holds
( H1 is Subgroup of H2 iff multMagma(# the carrier of (H1 /\ H2),the multF of (H1 /\ H2) #) = multMagma(# the carrier of H1,the multF of H1 #) )
let H2, H1 be Subgroup of G; :: thesis: ( H1 is Subgroup of H2 iff multMagma(# the carrier of (H1 /\ H2),the multF of (H1 /\ H2) #) = multMagma(# the carrier of H1,the multF of H1 #) )
thus ( H1 is Subgroup of H2 implies multMagma(# the carrier of (H1 /\ H2),the multF of (H1 /\ H2) #) = multMagma(# the carrier of H1,the multF of H1 #) ) :: thesis: ( multMagma(# the carrier of (H1 /\ H2),the multF of (H1 /\ H2) #) = multMagma(# the carrier of H1,the multF of H1 #) implies H1 is Subgroup of H2 )

proof

assume H1 is Subgroup of H2 ; :: thesis: multMagma(# the carrier of (H1 /\ H2),the multF of (H1 /\ H2) #) = multMagma(# the carrier of H1,the multF of H1 #)
then the carrier of H1 c= the carrier of H2 by Def5;
then ( the carrier of H1 /\ the carrier of H2 = the carrier of H1 & the carrier of (H1 /\ H2) = (carr H1) /\ (carr H2) & carr H1 = the carrier of H1 & carr H2 = the carrier of H2 ) by Def10, XBOOLE_1:28;
hence multMagma(# the carrier of (H1 /\ H2),the multF of (H1 /\ H2) #) = multMagma(# the carrier of H1,the multF of H1 #) by Th68; :: thesis: verum

end;

assume multMagma(# the carrier of (H1 /\ H2),the multF of (H1 /\ H2) #) = multMagma(# the carrier of H1,the multF of H1 #) ; :: thesis: H1 is Subgroup of H2
then the carrier of H1 = (carr H1) /\ (carr H2) by Def10
.= the carrier of H1 /\ the carrier of H2 ;
hence H1 is Subgroup of H2 by Th66, XBOOLE_1:17; :: thesis: verum