let f be non constant standard special_circular_sequence; :: thesis: for P being Subset of (TOP-REAL 2) st ( for p being Point of (TOP-REAL 2) st p in P holds
p `1 < ((GoB f) * 1,1) `1 ) holds
P misses L~ f
let P be Subset of (TOP-REAL 2); :: thesis: ( ( for p being Point of (TOP-REAL 2) st p in P holds
p `1 < ((GoB f) * 1,1) `1 ) implies P misses L~ f )
assume A1:
for p being Point of (TOP-REAL 2) st p in P holds
p `1 < ((GoB f) * 1,1) `1
; :: thesis: P misses L~ f
A2:
f is_sequence_on GoB f
by GOBOARD5:def 5;
assume
P meets L~ f
; :: thesis: contradiction
then consider x being set such that
A3:
x in P
and
A4:
x in L~ f
by XBOOLE_0:3;
reconsider x = x as Point of (TOP-REAL 2) by A3;
A5:
x `1 < ((GoB f) * 1,1) `1
by A1, A3;
consider i being Element of NAT such that
A6:
1 <= i
and
A7:
i + 1 <= len f
and
A8:
x in LSeg (f /. i),(f /. (i + 1))
by A4, SPPOL_2:14;
A9:
1 < width (GoB f)
by GOBOARD7:35;
per cases
( (f /. i) `1 <= (f /. (i + 1)) `1 or (f /. i) `1 >= (f /. (i + 1)) `1 )
;
suppose
(f /. i) `1 <= (f /. (i + 1)) `1
;
:: thesis: contradictionthen A10:
(f /. i) `1 <= x `1
by A8, TOPREAL1:9;
i <= len f
by A7, NAT_1:13;
then
i in dom f
by A6, FINSEQ_3:27;
then consider i1,
j1 being
Element of
NAT such that A11:
[i1,j1] in Indices (GoB f)
and A12:
f /. i = (GoB f) * i1,
j1
by A2, GOBOARD1:def 11;
A13:
( 1
<= j1 &
j1 <= width (GoB f) & 1
<= i1 &
i1 <= len (GoB f) )
by A11, MATRIX_1:39;
then A14:
(f /. i) `1 = ((GoB f) * i1,1) `1
by A12, GOBOARD5:3;
then
1
< i1
by A5, A10, A13, XXREAL_0:1;
then
((GoB f) * 1,1) `1 < (f /. i) `1
by A9, A13, A14, GOBOARD5:4;
hence
contradiction
by A1, A3, A10, XXREAL_0:2;
:: thesis: verum end; suppose
(f /. i) `1 >= (f /. (i + 1)) `1
;
:: thesis: contradictionthen A15:
(f /. (i + 1)) `1 <= x `1
by A8, TOPREAL1:9;
1
<= i + 1
by NAT_1:11;
then
i + 1
in dom f
by A7, FINSEQ_3:27;
then consider i1,
j1 being
Element of
NAT such that A16:
[i1,j1] in Indices (GoB f)
and A17:
f /. (i + 1) = (GoB f) * i1,
j1
by A2, GOBOARD1:def 11;
A18:
( 1
<= j1 &
j1 <= width (GoB f) & 1
<= i1 &
i1 <= len (GoB f) )
by A16, MATRIX_1:39;
then A19:
(f /. (i + 1)) `1 = ((GoB f) * i1,1) `1
by A17, GOBOARD5:3;
then
1
< i1
by A5, A15, A18, XXREAL_0:1;
then
((GoB f) * 1,1) `1 < (f /. (i + 1)) `1
by A9, A18, A19, GOBOARD5:4;
hence
contradiction
by A1, A3, A15, XXREAL_0:2;
:: thesis: verum end; end;