let L be Lattice; :: thesis: for F, H being Filter of L holds <.(F \/ H).) = { r where r is Element of L : ex p, q being Element of L st
( p "/\" q [= r & p in F & q in H ) }
let F, H be Filter of L; :: thesis: <.(F \/ H).) = { r where r is Element of L : ex p, q being Element of L st
( p "/\" q [= r & p in F & q in H ) }
set X = { r1 where r1 is Element of L : ex p, q being Element of L st
( p "/\" q [= r1 & p in F & q in H ) } ;
consider p1 being Element of L such that
A1:
p1 in F
by Th11;
consider q1 being Element of L such that
A2:
q1 in H
by Th11;
p1 "/\" q1 in { r1 where r1 is Element of L : ex p, q being Element of L st
( p "/\" q [= r1 & p in F & q in H ) }
by A1, A2;
then reconsider D = { r1 where r1 is Element of L : ex p, q being Element of L st
( p "/\" q [= r1 & p in F & q in H ) } as non empty set ;
D c= the carrier of L
then reconsider D = D as non empty Subset of L ;
A3:
for p, q being Element of L st p in D & q in D holds
p "/\" q in D
proof
let p,
q be
Element of
L;
:: thesis: ( p in D & q in D implies p "/\" q in D )
assume
p in D
;
:: thesis: ( not q in D or p "/\" q in D )
then A4:
ex
r1 being
Element of
L st
(
p = r1 & ex
p,
q being
Element of
L st
(
p "/\" q [= r1 &
p in F &
q in H ) )
;
assume
q in D
;
:: thesis: p "/\" q in D
then A5:
ex
r2 being
Element of
L st
(
q = r2 & ex
p,
q being
Element of
L st
(
p "/\" q [= r2 &
p in F &
q in H ) )
;
consider p1,
q1 being
Element of
L such that A6:
(
p1 "/\" q1 [= p &
p1 in F &
q1 in H )
by A4;
consider p2,
q2 being
Element of
L such that A7:
(
p2 "/\" q2 [= q &
p2 in F &
q2 in H )
by A5;
A8:
(p1 "/\" q1) "/\" (p2 "/\" q2) =
((p1 "/\" q1) "/\" p2) "/\" q2
by LATTICES:def 7
.=
((p1 "/\" p2) "/\" q1) "/\" q2
by LATTICES:def 7
.=
(p1 "/\" p2) "/\" (q1 "/\" q2)
by LATTICES:def 7
;
(
(p1 "/\" q1) "/\" (p2 "/\" q2) [= p "/\" (p2 "/\" q2) &
p "/\" (p2 "/\" q2) [= p "/\" q )
by A6, A7, LATTICES:27;
then
(
p1 "/\" p2 in F &
q1 "/\" q2 in H &
(p1 "/\" q1) "/\" (p2 "/\" q2) [= p "/\" q )
by A6, A7, Def1, LATTICES:25;
hence
p "/\" q in D
by A8;
:: thesis: verum
end;
for p, q being Element of L st p in D & p [= q holds
q in D
then reconsider D = D as Filter of L by A3, Th9;
A10:
F c= D
H c= D
then
F \/ H c= D
by A10, XBOOLE_1:8;
hence
<.(F \/ H).) c= { r1 where r1 is Element of L : ex p, q being Element of L st
( p "/\" q [= r1 & p in F & q in H ) }
by Def5; :: according to XBOOLE_0:def 10 :: thesis: { r where r is Element of L : ex p, q being Element of L st
( p "/\" q [= r & p in F & q in H ) } c= <.(F \/ H).)
let x be set ; :: according to TARSKI:def 3 :: thesis: ( not x in { r where r is Element of L : ex p, q being Element of L st
( p "/\" q [= r & p in F & q in H ) } or x in <.(F \/ H).) )
assume
x in { r1 where r1 is Element of L : ex p, q being Element of L st
( p "/\" q [= r1 & p in F & q in H ) }
; :: thesis: x in <.(F \/ H).)
then consider r being Element of L such that
A11:
( x = r & ex p, q being Element of L st
( p "/\" q [= r & p in F & q in H ) )
;
consider p, q being Element of L such that
A12:
( p "/\" q [= r & p in F & q in H )
by A11;
( F c= F \/ H & H c= F \/ H & F \/ H c= <.(F \/ H).) )
by Def5, XBOOLE_1:7;
then
( F c= <.(F \/ H).) & H c= <.(F \/ H).) )
by XBOOLE_1:1;
then
p "/\" q in <.(F \/ H).)
by A12, Def1;
hence
x in <.(F \/ H).)
by A11, A12, Th9; :: thesis: verum