let Z be open Subset of REAL ; :: thesis: for g being PartFunc of REAL ,REAL st Z c= dom (g (#) ln ) & g = #Z 2 & ( for x being Real st x in Z holds
x > 0 ) holds
( g (#) ln is_differentiable_on Z & ( for x being Real st x in Z holds
((g (#) ln ) `| Z) . x = x + ((2 * x) * (ln . x)) ) )
let g be PartFunc of REAL ,REAL ; :: thesis: ( Z c= dom (g (#) ln ) & g = #Z 2 & ( for x being Real st x in Z holds
x > 0 ) implies ( g (#) ln is_differentiable_on Z & ( for x being Real st x in Z holds
((g (#) ln ) `| Z) . x = x + ((2 * x) * (ln . x)) ) ) )
set f = ln ;
assume A1:
( Z c= dom (g (#) ln ) & g = #Z 2 & ( for x being Real st x in Z holds
x > 0 ) )
; :: thesis: ( g (#) ln is_differentiable_on Z & ( for x being Real st x in Z holds
((g (#) ln ) `| Z) . x = x + ((2 * x) * (ln . x)) ) )
then
Z c= (dom g) /\ (dom ln )
by VALUED_1:def 4;
then A2:
( Z c= dom g & Z c= dom ln )
by XBOOLE_1:18;
for x being Real st x in Z holds
g is_differentiable_in x
by A1, TAYLOR_1:2;
then A3:
g is_differentiable_on Z
by A2, FDIFF_1:16;
A4:
for x being Real st x in Z holds
(g `| Z) . x = 2 * x
A6:
( ln is_differentiable_on Z & ( for x being Real st x in Z holds
(ln `| Z) . x = 1 / x ) )
by A2, Th19;
now let x be
Real;
:: thesis: ( x in Z implies ((g (#) ln ) `| Z) . x = x + ((2 * x) * (ln . x)) )assume A7:
x in Z
;
:: thesis: ((g (#) ln ) `| Z) . x = x + ((2 * x) * (ln . x))then A8:
x <> 0
by A1;
((g (#) ln ) `| Z) . x =
((g . x) * (diff ln ,x)) + ((ln . x) * (diff g,x))
by A1, A3, A6, A7, FDIFF_1:29
.=
((g . x) * ((ln `| Z) . x)) + ((ln . x) * (diff g,x))
by A6, A7, FDIFF_1:def 8
.=
((g . x) * (1 / x)) + ((ln . x) * (diff g,x))
by A2, A7, Th19
.=
((x #Z 2) * (1 / x)) + ((ln . x) * (diff g,x))
by A1, TAYLOR_1:def 1
.=
((x #Z 2) * (1 / x)) + ((ln . x) * ((g `| Z) . x))
by A3, A7, FDIFF_1:def 8
.=
((x #Z (1 + 1)) * (1 / x)) + ((2 * x) * (ln . x))
by A4, A7
.=
(((x #Z 1) * (x #Z 1)) * (1 / x)) + ((2 * x) * (ln . x))
by TAYLOR_1:1
.=
(((x #Z 1) * x) * (1 / x)) + ((2 * x) * (ln . x))
by PREPOWER:45
.=
((x * x) * (1 / x)) + ((2 * x) * (ln . x))
by PREPOWER:45
.=
(x * (x * (1 / x))) + ((2 * x) * (ln . x))
.=
(x * 1) + ((2 * x) * (ln . x))
by A8, XCMPLX_1:107
.=
x + ((2 * x) * (ln . x))
;
hence
((g (#) ln ) `| Z) . x = x + ((2 * x) * (ln . x))
;
:: thesis: verum end;
hence
( g (#) ln is_differentiable_on Z & ( for x being Real st x in Z holds
((g (#) ln ) `| Z) . x = x + ((2 * x) * (ln . x)) ) )
by A1, A3, A6, FDIFF_1:29; :: thesis: verum