let a be Real; :: thesis: for Z being open Subset of REAL
for f1, f2 being PartFunc of REAL ,REAL st Z c= dom (f1 - f2) & ( for x being Real st x in Z holds
f1 . x = a ) & f2 = #Z 2 holds
( f1 - f2 is_differentiable_on Z & ( for x being Real st x in Z holds
((f1 - f2) `| Z) . x = - (2 * x) ) )
let Z be open Subset of REAL ; :: thesis: for f1, f2 being PartFunc of REAL ,REAL st Z c= dom (f1 - f2) & ( for x being Real st x in Z holds
f1 . x = a ) & f2 = #Z 2 holds
( f1 - f2 is_differentiable_on Z & ( for x being Real st x in Z holds
((f1 - f2) `| Z) . x = - (2 * x) ) )
let f1, f2 be PartFunc of REAL ,REAL ; :: thesis: ( Z c= dom (f1 - f2) & ( for x being Real st x in Z holds
f1 . x = a ) & f2 = #Z 2 implies ( f1 - f2 is_differentiable_on Z & ( for x being Real st x in Z holds
((f1 - f2) `| Z) . x = - (2 * x) ) ) )
assume A1:
( Z c= dom (f1 - f2) & ( for x being Real st x in Z holds
f1 . x = a ) & f2 = #Z 2 )
; :: thesis: ( f1 - f2 is_differentiable_on Z & ( for x being Real st x in Z holds
((f1 - f2) `| Z) . x = - (2 * x) ) )
then
Z c= (dom f1) /\ (dom f2)
by VALUED_1:12;
then A2:
( Z c= dom f1 & Z c= dom f2 )
by XBOOLE_1:18;
A3:
for x being Real st x in Z holds
f1 . x = (0 * x) + a
by A1;
then A4:
( f1 is_differentiable_on Z & ( for x being Real st x in Z holds
(f1 `| Z) . x = 0 ) )
by A2, FDIFF_1:31;
for x being Real st x in Z holds
f2 is_differentiable_in x
by A1, TAYLOR_1:2;
then A5:
f2 is_differentiable_on Z
by A2, FDIFF_1:16;
A6:
for x being Real st x in Z holds
(f2 `| Z) . x = 2 * (x #Z (2 - 1))
for x being Real st x in Z holds
((f1 - f2) `| Z) . x = - (2 * x)
proof
let x be
Real;
:: thesis: ( x in Z implies ((f1 - f2) `| Z) . x = - (2 * x) )
assume A8:
x in Z
;
:: thesis: ((f1 - f2) `| Z) . x = - (2 * x)
then
((f1 - f2) `| Z) . x = (diff f1,x) - (diff f2,x)
by A1, A4, A5, FDIFF_1:27;
hence ((f1 - f2) `| Z) . x =
((f1 `| Z) . x) - (diff f2,x)
by A4, A8, FDIFF_1:def 8
.=
((f1 `| Z) . x) - ((f2 `| Z) . x)
by A5, A8, FDIFF_1:def 8
.=
0 - ((f2 `| Z) . x)
by A2, A3, A8, FDIFF_1:31
.=
0 - (2 * (x #Z (2 - 1)))
by A6, A8
.=
0 - (2 * (x |^ 1))
by PREPOWER:46
.=
- (2 * (x |^ 1))
.=
- (2 * x)
by NEWTON:10
;
:: thesis: verum
end;
hence
( f1 - f2 is_differentiable_on Z & ( for x being Real st x in Z holds
((f1 - f2) `| Z) . x = - (2 * x) ) )
by A1, A4, A5, FDIFF_1:27; :: thesis: verum