let X be AffinPlane; :: thesis: ( X is satisfying_major_indirect_Scherungssatz implies X is satisfying_major_Scherungssatz )
assume A1:
X is satisfying_major_indirect_Scherungssatz
; :: thesis: X is satisfying_major_Scherungssatz
now let o,
a1,
a2,
a3,
a4,
b1,
b2,
b3,
b4 be
Element of
X;
:: thesis: for M, N being Subset of X st M is being_line & N is being_line & o in M & o in N & a1 in M & a3 in M & b1 in M & b3 in M & a2 in N & a4 in N & b2 in N & b4 in N & not a4 in M & not a2 in M & not b2 in M & not b4 in M & not a1 in N & not a3 in N & not b1 in N & not b3 in N & a3,a2 // b3,b2 & a2,a1 // b2,b1 & a1,a4 // b1,b4 holds
a3,a4 // b3,b4let M,
N be
Subset of
X;
:: thesis: ( M is being_line & N is being_line & o in M & o in N & a1 in M & a3 in M & b1 in M & b3 in M & a2 in N & a4 in N & b2 in N & b4 in N & not a4 in M & not a2 in M & not b2 in M & not b4 in M & not a1 in N & not a3 in N & not b1 in N & not b3 in N & a3,a2 // b3,b2 & a2,a1 // b2,b1 & a1,a4 // b1,b4 implies a3,a4 // b3,b4 )assume A2:
(
M is
being_line &
N is
being_line &
o in M &
o in N &
a1 in M &
a3 in M &
b1 in M &
b3 in M &
a2 in N &
a4 in N &
b2 in N &
b4 in N & not
a4 in M & not
a2 in M & not
b2 in M & not
b4 in M & not
a1 in N & not
a3 in N & not
b1 in N & not
b3 in N &
a3,
a2 // b3,
b2 &
a2,
a1 // b2,
b1 &
a1,
a4 // b1,
b4 )
;
:: thesis: a3,a4 // b3,b4then A3:
not
M // N
by AFF_1:59;
A4:
(
M // M &
N // N )
by A2, AFF_1:55;
A5:
now assume A6:
(
a1 = a3 or
a2 = a4 )
;
:: thesis: a3,a4 // b3,b4A7:
now assume A8:
a1 = a3
;
:: thesis: a3,a4 // b3,b4A9:
not
LIN o,
b2,
b1
by A2, AFF_1:39;
o,
b1 // o,
b3
by A2, A4, AFF_1:53;
then A10:
LIN o,
b1,
b3
by AFF_1:def 1;
b2,
b1 // b2,
b3
hence
a3,
a4 // b3,
b4
by A2, A8, A9, A10, AFF_1:23;
:: thesis: verum end; now assume A11:
a2 = a4
;
:: thesis: a3,a4 // b3,b4A12:
not
LIN o,
b1,
b2
by A2, AFF_1:39;
o,
b2 // o,
b4
by A2, A4, AFF_1:53;
then A13:
LIN o,
b2,
b4
by AFF_1:def 1;
b1,
b2 // b1,
b4
hence
a3,
a4 // b3,
b4
by A2, A11, A12, A13, AFF_1:23;
:: thesis: verum end; hence
a3,
a4 // b3,
b4
by A6, A7;
:: thesis: verum end; now assume A14:
(
a1 <> a3 &
a2 <> a4 )
;
:: thesis: a3,a4 // b3,b4consider d1 being
Element of
X such that A15:
(
o <> d1 &
d1 in N )
by A2;
ex
d2 being
Element of
X st
(
d2 in M &
a2,
a1 // d2,
d1 )
proof
consider e1 being
Element of
X such that A16:
(
o <> e1 &
e1 in M )
by A2;
consider e2 being
Element of
X such that A17:
(
a2,
a1 // d1,
e2 &
d1 <> e2 )
by DIRAF:47;
not
o,
e1 // d1,
e2
proof
assume
o,
e1 // d1,
e2
;
:: thesis: contradiction
then A18:
o,
e1 // a2,
a1
by A17, AFF_1:14;
o,
e1 // a1,
a3
by A2, A4, A16, AFF_1:53;
then
a1,
a3 // a2,
a1
by A16, A18, AFF_1:14;
then
a1,
a3 // a1,
a2
by AFF_1:13;
then
LIN a1,
a3,
a2
by AFF_1:def 1;
hence
contradiction
by A2, A14, AFF_1:39;
:: thesis: verum
end;
then consider d2 being
Element of
X such that A19:
(
LIN o,
e1,
d2 &
LIN d1,
e2,
d2 )
by AFF_1:74;
take
d2
;
:: thesis: ( d2 in M & a2,a1 // d2,d1 )
d1,
e2 // d1,
d2
by A19, AFF_1:def 1;
then
a2,
a1 // d1,
d2
by A17, AFF_1:14;
hence
(
d2 in M &
a2,
a1 // d2,
d1 )
by A2, A16, A19, AFF_1:13, AFF_1:39;
:: thesis: verum
end; then consider d2 being
Element of
X such that A20:
(
d2 in M &
a2,
a1 // d2,
d1 )
;
ex
d3 being
Element of
X st
(
d3 in N &
a3,
a2 // d3,
d2 )
proof
consider e1 being
Element of
X such that A21:
(
o <> e1 &
e1 in N )
by A2;
consider e2 being
Element of
X such that A22:
(
a3,
a2 // d2,
e2 &
d2 <> e2 )
by DIRAF:47;
not
o,
e1 // d2,
e2
proof
assume
o,
e1 // d2,
e2
;
:: thesis: contradiction
then A23:
o,
e1 // a3,
a2
by A22, AFF_1:14;
o,
e1 // a2,
a4
by A2, A4, A21, AFF_1:53;
then
a2,
a4 // a3,
a2
by A21, A23, AFF_1:14;
then
a2,
a4 // a2,
a3
by AFF_1:13;
then
LIN a2,
a4,
a3
by AFF_1:def 1;
hence
contradiction
by A2, A14, AFF_1:39;
:: thesis: verum
end;
then consider d3 being
Element of
X such that A24:
(
LIN o,
e1,
d3 &
LIN d2,
e2,
d3 )
by AFF_1:74;
take
d3
;
:: thesis: ( d3 in N & a3,a2 // d3,d2 )
d2,
e2 // d2,
d3
by A24, AFF_1:def 1;
then
a3,
a2 // d2,
d3
by A22, AFF_1:14;
hence
(
d3 in N &
a3,
a2 // d3,
d2 )
by A2, A21, A24, AFF_1:13, AFF_1:39;
:: thesis: verum
end; then consider d3 being
Element of
X such that A25:
(
d3 in N &
a3,
a2 // d3,
d2 )
;
ex
d4 being
Element of
X st
(
d4 in M &
a1,
a4 // d1,
d4 )
proof
consider e1 being
Element of
X such that A26:
(
o <> e1 &
e1 in M )
by A2;
consider e2 being
Element of
X such that A27:
(
a1,
a4 // d1,
e2 &
d1 <> e2 )
by DIRAF:47;
not
o,
e1 // d1,
e2
proof
assume
o,
e1 // d1,
e2
;
:: thesis: contradiction
then A28:
o,
e1 // a1,
a4
by A27, AFF_1:14;
o,
e1 // a1,
a3
by A2, A4, A26, AFF_1:53;
then
a1,
a3 // a1,
a4
by A26, A28, AFF_1:14;
then
LIN a1,
a3,
a4
by AFF_1:def 1;
hence
contradiction
by A2, A14, AFF_1:39;
:: thesis: verum
end;
then consider d4 being
Element of
X such that A29:
(
LIN o,
e1,
d4 &
LIN d1,
e2,
d4 )
by AFF_1:74;
take
d4
;
:: thesis: ( d4 in M & a1,a4 // d1,d4 )
d1,
e2 // d1,
d4
by A29, AFF_1:def 1;
hence
(
d4 in M &
a1,
a4 // d1,
d4 )
by A2, A26, A27, A29, AFF_1:14, AFF_1:39;
:: thesis: verum
end; then consider d4 being
Element of
X such that A30:
(
d4 in M &
a1,
a4 // d1,
d4 )
;
A31:
(
d2 <> o &
d3 <> o &
d4 <> o )
proof
assume A32:
( not
d2 <> o or not
d3 <> o or not
d4 <> o )
;
:: thesis: contradiction
A33:
now assume A34:
d2 = o
;
:: thesis: contradiction
o,
d1 // a2,
a4
by A2, A4, A15, AFF_1:53;
then
a2,
a4 // a2,
a1
by A15, A20, A34, AFF_1:14;
then
LIN a2,
a4,
a1
by AFF_1:def 1;
hence
contradiction
by A2, A14, AFF_1:39;
:: thesis: verum end;
A35:
now assume A36:
d3 = o
;
:: thesis: contradiction
o,
d2 // a3,
a1
by A2, A4, A20, AFF_1:53;
then
a3,
a1 // a3,
a2
by A25, A33, A36, AFF_1:14;
then
LIN a3,
a1,
a2
by AFF_1:def 1;
hence
contradiction
by A2, A14, AFF_1:39;
:: thesis: verum end;
now assume A37:
d4 = o
;
:: thesis: contradiction
d1,
o // a2,
a4
by A2, A4, A15, AFF_1:53;
then
a1,
a4 // a2,
a4
by A15, A30, A37, AFF_1:14;
then
a4,
a2 // a4,
a1
by AFF_1:13;
then
LIN a4,
a2,
a1
by AFF_1:def 1;
hence
contradiction
by A2, A14, AFF_1:39;
:: thesis: verum end;
hence
contradiction
by A32, A33, A35;
:: thesis: verum
end; A38:
( not
d1 in M & not
d3 in M & not
d2 in N & not
d4 in N )
proof
assume
(
d1 in M or
d3 in M or
d2 in N or
d4 in N )
;
:: thesis: contradiction
then A39:
(
o,
d1 // M or
o,
d3 // M or
o,
d2 // N or
o,
d4 // N )
by A2, AFF_1:66;
(
o,
d1 // N &
o,
d3 // N &
o,
d2 // M &
o,
d4 // M )
by A2, A15, A20, A25, A30, AFF_1:66;
hence
contradiction
by A3, A15, A31, A39, AFF_1:67;
:: thesis: verum
end; then A40:
a3,
a4 // d3,
d4
by A1, A2, A15, A20, A25, A30, Def6;
A41:
(
d1 <> d2 &
d2 <> d3 &
d3 <> d4 &
d4 <> d1 )
proof
assume
( not
d1 <> d2 or not
d2 <> d3 or not
d3 <> d4 or not
d4 <> d1 )
;
:: thesis: contradiction
then A42:
(
o,
d1 // M or
o,
d3 // M )
by A2, A20, A30, AFF_1:66;
(
o,
d1 // N &
o,
d3 // N )
by A2, A15, A25, AFF_1:66;
hence
contradiction
by A3, A15, A31, A42, AFF_1:67;
:: thesis: verum
end; A43:
b2,
b1 // d2,
d1
by A2, A20, AFF_1:14;
A44:
b3,
b2 // d3,
d2
by A2, A25, AFF_1:14;
b1,
b4 // d1,
d4
by A2, A30, AFF_1:14;
then
b3,
b4 // d3,
d4
by A1, A2, A15, A20, A25, A30, A38, A43, A44, Def6;
hence
a3,
a4 // b3,
b4
by A40, A41, AFF_1:14;
:: thesis: verum end; hence
a3,
a4 // b3,
b4
by A5;
:: thesis: verum end;
hence
X is satisfying_major_Scherungssatz
by Def2; :: thesis: verum