set sin1 = sin | [.(PI / 2),((3 / 2) * PI ).];
now let y be
set ;
:: thesis: ( ( y in [.(- 1),1.] implies ex x being set st
( x in dom (sin | [.(PI / 2),((3 / 2) * PI ).]) & y = (sin | [.(PI / 2),((3 / 2) * PI ).]) . x ) ) & ( ex x being set st
( x in dom (sin | [.(PI / 2),((3 / 2) * PI ).]) & y = (sin | [.(PI / 2),((3 / 2) * PI ).]) . x ) implies y in [.(- 1),1.] ) )thus
(
y in [.(- 1),1.] implies ex
x being
set st
(
x in dom (sin | [.(PI / 2),((3 / 2) * PI ).]) &
y = (sin | [.(PI / 2),((3 / 2) * PI ).]) . x ) )
:: thesis: ( ex x being set st
( x in dom (sin | [.(PI / 2),((3 / 2) * PI ).]) & y = (sin | [.(PI / 2),((3 / 2) * PI ).]) . x ) implies y in [.(- 1),1.] )proof
assume A1:
y in [.(- 1),1.]
;
:: thesis: ex x being set st
( x in dom (sin | [.(PI / 2),((3 / 2) * PI ).]) & y = (sin | [.(PI / 2),((3 / 2) * PI ).]) . x )
then reconsider y1 =
y as
Real ;
A2:
(sin | [.(PI / 2),((3 / 2) * PI ).]) | [.(PI / 2),((3 / 2) * PI ).] is
continuous
;
X:
dom (sin | [.(PI / 2),((3 / 2) * PI ).]) =
[.(PI / 2),((3 / 2) * PI ).] /\ REAL
by RELAT_1:90, SIN_COS:27
.=
[.(PI / 2),((3 / 2) * PI ).]
by XBOOLE_1:28
;
(
PI / 2
in [.(PI / 2),((3 / 2) * PI ).] &
(3 / 2) * PI in [.(PI / 2),((3 / 2) * PI ).] )
by Lx4, XXREAL_1:1;
then
(
(sin | [.(PI / 2),((3 / 2) * PI ).]) . (PI / 2) = sin . (PI / 2) &
(sin | [.(PI / 2),((3 / 2) * PI ).]) . ((3 / 2) * PI ) = sin . ((3 / 2) * PI ) )
by FUNCT_1:72;
then
y1 in [.((sin | [.(PI / 2),((3 / 2) * PI ).]) . (PI / 2)),((sin | [.(PI / 2),((3 / 2) * PI ).]) . ((3 / 2) * PI )).] \/ [.((sin | [.(PI / 2),((3 / 2) * PI ).]) . ((3 / 2) * PI )),((sin | [.(PI / 2),((3 / 2) * PI ).]) . (PI / 2)).]
by A1, SIN_COS:81, XBOOLE_0:def 3;
then consider x being
Real such that A3:
x in [.(PI / 2),((3 / 2) * PI ).]
and A4:
y1 = (sin | [.(PI / 2),((3 / 2) * PI ).]) . x
by A2, Lx4, X, FCONT_2:16;
take
x
;
:: thesis: ( x in dom (sin | [.(PI / 2),((3 / 2) * PI ).]) & y = (sin | [.(PI / 2),((3 / 2) * PI ).]) . x )
x in REAL /\ [.(PI / 2),((3 / 2) * PI ).]
by A3, XBOOLE_0:def 4;
hence
(
x in dom (sin | [.(PI / 2),((3 / 2) * PI ).]) &
y = (sin | [.(PI / 2),((3 / 2) * PI ).]) . x )
by A4, RELAT_1:90, SIN_COS:27;
:: thesis: verum
end; thus
( ex
x being
set st
(
x in dom (sin | [.(PI / 2),((3 / 2) * PI ).]) &
y = (sin | [.(PI / 2),((3 / 2) * PI ).]) . x ) implies
y in [.(- 1),1.] )
:: thesis: verum end;
hence
rng (sin | [.(PI / 2),((3 / 2) * PI ).]) = [.(- 1),1.]
by FUNCT_1:def 5; :: thesis: verum