now let y be
set ;
:: thesis: ( ( y in [.(- 1),1.] implies ex x being set st
( x in dom cos & y = cos . x ) ) & ( ex x being set st
( x in dom cos & y = cos . x ) implies y in [.(- 1),1.] ) )thus
(
y in [.(- 1),1.] implies ex
x being
set st
(
x in dom cos &
y = cos . x ) )
:: thesis: ( ex x being set st
( x in dom cos & y = cos . x ) implies y in [.(- 1),1.] )proof
assume A1:
y in [.(- 1),1.]
;
:: thesis: ex x being set st
( x in dom cos & y = cos . x )
then reconsider y1 =
y as
Real ;
A2:
cos | [.0 ,PI .] is
continuous
;
y1 in [.(cos . 0 ),(cos . PI ).] \/ [.(cos . PI ),(cos . 0 ).]
by A1, SIN_COS:33, SIN_COS:81, XBOOLE_0:def 3;
then consider x being
Real such that
x in [.0 ,PI .]
and A3:
y1 = cos . x
by A2, FCONT_2:16, SIN_COS:27;
take
x
;
:: thesis: ( x in dom cos & y = cos . x )
thus
(
x in dom cos &
y = cos . x )
by A3, SIN_COS:27;
:: thesis: verum
end; thus
( ex
x being
set st
(
x in dom cos &
y = cos . x ) implies
y in [.(- 1),1.] )
by Th45, SIN_COS:27;
:: thesis: verum end;
hence
rng cos = [.(- 1),1.]
by FUNCT_1:def 5; :: thesis: verum