let n be Element of NAT ; :: thesis: for x being Element of COMPLEX n
for A being Subset of (COMPLEX n) st not x in A & A <> {} & A is closed holds
dist x,A > 0
let x be Element of COMPLEX n; :: thesis: for A being Subset of (COMPLEX n) st not x in A & A <> {} & A is closed holds
dist x,A > 0
let A be Subset of (COMPLEX n); :: thesis: ( not x in A & A <> {} & A is closed implies dist x,A > 0 )
assume that
A1:
not x in A
and
A2:
A <> {}
and
A3:
for x being Element of COMPLEX n st ( for r being Real st r > 0 holds
ex z being Element of COMPLEX n st
( |.z.| < r & x + z in A ) ) holds
x in A
and
A4:
dist x,A <= 0
; :: according to COMPLSP1:def 16 :: thesis: contradiction
A5:
dist x,A = 0
by A2, A4, Th85;
now let r be
Real;
:: thesis: ( r > 0 implies ex z being Element of COMPLEX n st
( |.z.| < r & x + z in A ) )assume A6:
r > 0
;
:: thesis: ex z being Element of COMPLEX n st
( |.z.| < r & x + z in A )defpred S1[
set ]
means $1
in A;
deffunc H1(
Element of
COMPLEX n)
-> Real =
|.(x - $1).|;
reconsider X =
{ H1(z) where z is Element of COMPLEX n : S1[z] } as
Subset of
REAL from COMPLSP1:sch 1();
A7:
dist x,
A = lower_bound X
by Def18;
consider z being
Element of
COMPLEX n such that A8:
z in A
by A2, SUBSET_1:10;
A9:
|.(x - z).| in X
by A8;
A10:
X is
bounded_below
0 + r = r
;
then consider r' being
real number such that A11:
(
r' in X &
r' < r )
by A5, A6, A7, A9, A10, SEQ_4:def 5;
consider z1 being
Element of
COMPLEX n such that A12:
(
r' = |.(x - z1).| &
z1 in A )
by A11;
take z =
z1 - x;
:: thesis: ( |.z.| < r & x + z in A )thus
(
|.z.| < r &
x + z in A )
by A11, A12, Th50, Th74;
:: thesis: verum end;
hence
contradiction
by A1, A3; :: thesis: verum