let T be non empty T_1 TopSpace; :: thesis: ( ( for A being Subset of T st not A is finite & A is countable holds
not Der A is empty ) implies T is countably_compact )
assume A1:
for A being Subset of T st not A is finite & A is countable holds
not Der A is empty
; :: thesis: T is countably_compact
assume
not T is countably_compact
; :: thesis: contradiction
then consider S being non-empty closed SetSequence of T such that
A2:
( S is non-ascending & meet S = {} )
by Th22;
defpred S1[ set , set ] means $2 in S . $1;
A3:
for x being set st x in NAT holds
ex y being set st
( y in the carrier of T & S1[x,y] )
consider F being sequence of T such that
A6:
for x being set st x in NAT holds
S1[x,F . x]
from FUNCT_2:sch 1(A3);
reconsider rngF = rng F as Subset of T ;
dom F = NAT
by FUNCT_2:def 1;
then
rng F is countable
by CARD_3:127;
then
not Der rngF is empty
by A1, B7, A2, Th25;
then consider p being set such that
A8:
p in Der rngF
by XBOOLE_0:def 1;
reconsider p = p as Point of T by A8;
consider n being Element of NAT such that
A9:
not p in S . n
by A2, KURATO_2:6;
deffunc H1( set ) -> set = F . $1;
set F1n = { H1(i) where i is Element of NAT : i in n + 1 } ;
A10:
n + 1 is finite
;
A11:
{ H1(i) where i is Element of NAT : i in n + 1 } is finite
from FRAENKEL:sch 21(A10);
{ H1(i) where i is Element of NAT : i in n + 1 } c= the carrier of T
then reconsider F1n = { H1(i) where i is Element of NAT : i in n + 1 } as Subset of T ;
set U = ((S . n) ` ) \ (F1n \ {p});
reconsider U = ((S . n) ` ) \ (F1n \ {p}) as Subset of T ;
( F1n \ {p} is finite & S . n is closed )
by A11, Def6;
then A13:
U is open
by FRECHET:4;
p in {p}
by TARSKI:def 1;
then
( not p in F1n \ {p} & p in (S . n) ` )
by A9, XBOOLE_0:def 5;
then
p in U
by XBOOLE_0:def 5;
then consider q being Point of T such that
A14:
( q in rngF /\ U & q <> p )
by A8, A13, TOPGEN_1:19;
q in rngF
by A14, XBOOLE_0:def 4;
then consider i being set such that
A15:
( i in dom F & F . i = q )
by FUNCT_1:def 5;
reconsider i = i as Element of NAT by A15;