let x, y be set ; :: thesis: for Ch, F being Function st x in Ch " {y} holds
(Intersection F,(Ch | ((dom Ch) \ {x})),y) /\ (F . x) = Intersection F,Ch,y
let Ch, F be Function; :: thesis: ( x in Ch " {y} implies (Intersection F,(Ch | ((dom Ch) \ {x})),y) /\ (F . x) = Intersection F,Ch,y )
assume A1:
x in Ch " {y}
; :: thesis: (Intersection F,(Ch | ((dom Ch) \ {x})),y) /\ (F . x) = Intersection F,Ch,y
set d = (dom Ch) \ {x};
set Chd = Ch | ((dom Ch) \ {x});
set I1 = Intersection F,Ch,y;
set I2 = Intersection F,(Ch | ((dom Ch) \ {x})),y;
( Intersection F,Ch,y c= F . x & Intersection F,Ch,y c= Intersection F,(Ch | ((dom Ch) \ {x})),y )
by A1, Th29, Th33;
then A2:
Intersection F,Ch,y c= (Intersection F,(Ch | ((dom Ch) \ {x})),y) /\ (F . x)
by XBOOLE_1:19;
(Intersection F,(Ch | ((dom Ch) \ {x})),y) /\ (F . x) c= Intersection F,Ch,y
proof
let z be
set ;
:: according to TARSKI:def 3 :: thesis: ( not z in (Intersection F,(Ch | ((dom Ch) \ {x})),y) /\ (F . x) or z in Intersection F,Ch,y )
assume A3:
z in (Intersection F,(Ch | ((dom Ch) \ {x})),y) /\ (F . x)
;
:: thesis: z in Intersection F,Ch,y
hence
z in Intersection F,
Ch,
y
by A3, Def2;
:: thesis: verum
end;
hence
(Intersection F,(Ch | ((dom Ch) \ {x})),y) /\ (F . x) = Intersection F,Ch,y
by A2, XBOOLE_0:def 10; :: thesis: verum