let Y be non empty set ; :: thesis: for a, b, c being Element of Funcs Y,BOOLEAN holds (a 'imp' b) '&' (b 'imp' c) = ((a 'imp' b) '&' (b 'imp' c)) '&' (a 'imp' c)
let a, b, c be Element of Funcs Y,BOOLEAN ; :: thesis: (a 'imp' b) '&' (b 'imp' c) = ((a 'imp' b) '&' (b 'imp' c)) '&' (a 'imp' c)
A1:
for x being Element of Y holds ((a 'imp' b) '&' (b 'imp' c)) . x = (((a 'imp' b) '&' (b 'imp' c)) '&' (a 'imp' c)) . x
consider k3 being Function such that
A7:
( (a 'imp' b) '&' (b 'imp' c) = k3 & dom k3 = Y & rng k3 c= BOOLEAN )
by FUNCT_2:def 2;
consider k4 being Function such that
A8:
( ((a 'imp' b) '&' (b 'imp' c)) '&' (a 'imp' c) = k4 & dom k4 = Y & rng k4 c= BOOLEAN )
by FUNCT_2:def 2;
( Y = dom k3 & Y = dom k4 & ( for u being set st u in Y holds
k3 . u = k4 . u ) )
by A1, A7, A8;
hence
(a 'imp' b) '&' (b 'imp' c) = ((a 'imp' b) '&' (b 'imp' c)) '&' (a 'imp' c)
by A7, A8, FUNCT_1:9; :: thesis: verum