let T1, T2 be Tree; :: thesis: ( ( T1 is binary & T2 is binary ) iff tree T1,T2 is binary )
set RT = tree T1,T2;
hereby :: thesis: ( tree T1,T2 is binary implies ( T1 is binary & T2 is binary ) )
assume A1:
(
T1 is
binary &
T2 is
binary )
;
:: thesis: tree T1,T2 is binary now let t be
Element of
tree T1,
T2;
:: thesis: ( not t in Leaves (tree T1,T2) implies succ b1 = {(b1 ^ <*0 *>),(b1 ^ <*1*>)} )assume A2:
not
t in Leaves (tree T1,T2)
;
:: thesis: succ b1 = {(b1 ^ <*0 *>),(b1 ^ <*1*>)}per cases
( t = {} or ex p being FinSequence st
( ( p in T1 & t = <*0 *> ^ p ) or ( p in T2 & t = <*1*> ^ p ) ) )
by TREES_3:71;
suppose
ex
p being
FinSequence st
( (
p in T1 &
t = <*0 *> ^ p ) or (
p in T2 &
t = <*1*> ^ p ) )
;
:: thesis: succ b1 = {(b1 ^ <*0 *>),(b1 ^ <*1*>)}then consider p being
FinSequence such that A3:
( (
p in T1 &
t = <*0 *> ^ p ) or (
p in T2 &
t = <*1*> ^ p ) )
;
A4:
now assume A5:
(
p in T1 &
t = <*0 *> ^ p )
;
:: thesis: succ t = {(t ^ <*0 *>),(t ^ <*1*>)}then reconsider p =
p as
Element of
T1 ;
per cases
( p in Leaves T1 or not p in Leaves T1 )
;
suppose
not
p in Leaves T1
;
:: thesis: succ t = {(t ^ <*0 *>),(t ^ <*1*>)}then A6:
succ p = {(p ^ <*0 *>),(p ^ <*1*>)}
by A1, Def2;
now let x be
set ;
:: thesis: ( ( x in succ t implies x in {(t ^ <*0 *>),(t ^ <*1*>)} ) & ( x in {(t ^ <*0 *>),(t ^ <*1*>)} implies x in succ t ) )hereby :: thesis: ( x in {(t ^ <*0 *>),(t ^ <*1*>)} implies x in succ t )
assume A7:
x in succ t
;
:: thesis: x in {(t ^ <*0 *>),(t ^ <*1*>)}then
x in { (t ^ <*n*>) where n is Element of NAT : t ^ <*n*> in tree T1,T2 }
by TREES_2:def 5;
then consider n being
Element of
NAT such that A8:
(
x = t ^ <*n*> &
t ^ <*n*> in tree T1,
T2 )
;
A9:
x = <*0 *> ^ (p ^ <*n*>)
by A5, A8, FINSEQ_1:45;
then reconsider pn =
p ^ <*n*> as
Element of
T1 by A8, TREES_3:72;
pn in succ p
by A5, A7, A9, Th9;
then
(
pn = p ^ <*0 *> or
pn = p ^ <*1*> )
by A6, TARSKI:def 2;
then
(
x = t ^ <*0 *> or
x = t ^ <*1*> )
by A8, FINSEQ_1:46;
hence
x in {(t ^ <*0 *>),(t ^ <*1*>)}
by TARSKI:def 2;
:: thesis: verum
end; assume
x in {(t ^ <*0 *>),(t ^ <*1*>)}
;
:: thesis: x in succ tthen
(
x = (<*0 *> ^ p) ^ <*0 *> or
x = (<*0 *> ^ p) ^ <*1*> )
by A5, TARSKI:def 2;
then A10:
(
x = <*0 *> ^ (p ^ <*0 *>) or
x = <*0 *> ^ (p ^ <*1*>) )
by FINSEQ_1:45;
(
p ^ <*0 *> in succ p &
p ^ <*1*> in succ p )
by A6, TARSKI:def 2;
hence
x in succ t
by A5, A10, Th9;
:: thesis: verum end; hence
succ t = {(t ^ <*0 *>),(t ^ <*1*>)}
by TARSKI:2;
:: thesis: verum end; end; end; now assume A11:
(
p in T2 &
t = <*1*> ^ p )
;
:: thesis: succ t = {(t ^ <*0 *>),(t ^ <*1*>)}then reconsider p =
p as
Element of
T2 ;
per cases
( p in Leaves T2 or not p in Leaves T2 )
;
suppose
not
p in Leaves T2
;
:: thesis: succ t = {(t ^ <*0 *>),(t ^ <*1*>)}then A12:
succ p = {(p ^ <*0 *>),(p ^ <*1*>)}
by A1, Def2;
now let x be
set ;
:: thesis: ( ( x in succ t implies x in {(t ^ <*0 *>),(t ^ <*1*>)} ) & ( x in {(t ^ <*0 *>),(t ^ <*1*>)} implies x in succ t ) )hereby :: thesis: ( x in {(t ^ <*0 *>),(t ^ <*1*>)} implies x in succ t )
assume A13:
x in succ t
;
:: thesis: x in {(t ^ <*0 *>),(t ^ <*1*>)}then
x in { (t ^ <*n*>) where n is Element of NAT : t ^ <*n*> in tree T1,T2 }
by TREES_2:def 5;
then consider n being
Element of
NAT such that A14:
(
x = t ^ <*n*> &
t ^ <*n*> in tree T1,
T2 )
;
A15:
x = <*1*> ^ (p ^ <*n*>)
by A11, A14, FINSEQ_1:45;
then reconsider pn =
p ^ <*n*> as
Element of
T2 by A14, TREES_3:73;
pn in succ p
by A11, A13, A15, Th9;
then
(
pn = p ^ <*0 *> or
pn = p ^ <*1*> )
by A12, TARSKI:def 2;
then
(
x = t ^ <*0 *> or
x = t ^ <*1*> )
by A14, FINSEQ_1:46;
hence
x in {(t ^ <*0 *>),(t ^ <*1*>)}
by TARSKI:def 2;
:: thesis: verum
end; assume
x in {(t ^ <*0 *>),(t ^ <*1*>)}
;
:: thesis: x in succ tthen
(
x = (<*1*> ^ p) ^ <*0 *> or
x = (<*1*> ^ p) ^ <*1*> )
by A11, TARSKI:def 2;
then A16:
(
x = <*1*> ^ (p ^ <*0 *>) or
x = <*1*> ^ (p ^ <*1*>) )
by FINSEQ_1:45;
(
p ^ <*0 *> in succ p &
p ^ <*1*> in succ p )
by A12, TARSKI:def 2;
hence
x in succ t
by A11, A16, Th9;
:: thesis: verum end; hence
succ t = {(t ^ <*0 *>),(t ^ <*1*>)}
by TARSKI:2;
:: thesis: verum end; end; end; hence
succ t = {(t ^ <*0 *>),(t ^ <*1*>)}
by A3, A4;
:: thesis: verum end; end; end; hence
tree T1,
T2 is
binary
by Def2;
:: thesis: verum
end;
assume A17:
tree T1,T2 is binary
; :: thesis: ( T1 is binary & T2 is binary )
hence
T1 is binary
by Def2; :: thesis: T2 is binary
hence
T2 is binary
by Def2; :: thesis: verum