let X be BCI-algebra; :: thesis: ( X is BCK-algebra of 1, 0 , 0 , 0 iff ( X is BCK-algebra of 0 , 0 , 0 , 0 & X is BCK-algebra of 0 ,1, 0 ,1 ) )
thus
( X is BCK-algebra of 1, 0 , 0 , 0 implies ( X is BCK-algebra of 0 , 0 , 0 , 0 & X is BCK-algebra of 0 ,1, 0 ,1 ) )
:: thesis: ( X is BCK-algebra of 0 , 0 , 0 , 0 & X is BCK-algebra of 0 ,1, 0 ,1 implies X is BCK-algebra of 1, 0 , 0 , 0 )proof
assume
X is
BCK-algebra of 1,
0 ,
0 ,
0
;
:: thesis: ( X is BCK-algebra of 0 , 0 , 0 , 0 & X is BCK-algebra of 0 ,1, 0 ,1 )
then
X is
BCK-implicative BCK-algebra
by Th47;
hence
(
X is
BCK-algebra of
0 ,
0 ,
0 ,
0 &
X is
BCK-algebra of
0 ,1,
0 ,1 )
by Th46, Th41;
:: thesis: verum
end;
assume A1:
( X is BCK-algebra of 0 , 0 , 0 , 0 & X is BCK-algebra of 0 ,1, 0 ,1 )
; :: thesis: X is BCK-algebra of 1, 0 , 0 , 0
then A2:
X is commutative BCK-algebra
by Th41;
X is BCK-positive-implicative BCK-algebra
by A1, Th46;
then
X is BCK-implicative BCK-algebra
by A2, BCIALG_3:34;
hence
X is BCK-algebra of 1, 0 , 0 , 0
by Th47; :: thesis: verum