let X, Y be finite natural-membered set ; :: thesis: for i being Nat st X <N< Y & i in card X holds
(Sgm0 (X \/ Y)) . i in X
let i be Nat; :: thesis: ( X <N< Y & i in card X implies (Sgm0 (X \/ Y)) . i in X )
assume A1:
( X <N< Y & i in card X )
; :: thesis: (Sgm0 (X \/ Y)) . i in X
A20:
X \/ Y <> {}
by A1, CARD_1:47, XBOOLE_1:15;
set f0 = Sgm0 (X \/ Y);
A30:
rng (Sgm0 (X \/ Y)) = X \/ Y
by AC113;
set f = (Sgm0 (X \/ Y)) | (card X);
set Z = { v where v is Element of X \/ Y : ex k2 being Nat st
( v = ((Sgm0 (X \/ Y)) | (card X)) . k2 & k2 in card X ) } ;
A33:
len (Sgm0 (X \/ Y)) = card (X \/ Y)
by Th44;
A22:
card X <= len (Sgm0 (X \/ Y))
by A33, NAT_1:44, XBOOLE_1:7;
then A4:
len ((Sgm0 (X \/ Y)) | (card X)) = card X
by TH80;
B4:
rng ((Sgm0 (X \/ Y)) | (card X)) c= rng (Sgm0 (X \/ Y))
by RELAT_1:99;
A3:
rng ((Sgm0 (X \/ Y)) | (card X)) c= { v where v is Element of X \/ Y : ex k2 being Nat st
( v = ((Sgm0 (X \/ Y)) | (card X)) . k2 & k2 in card X ) }
{ v where v is Element of X \/ Y : ex k2 being Nat st
( v = ((Sgm0 (X \/ Y)) | (card X)) . k2 & k2 in card X ) } c= rng ((Sgm0 (X \/ Y)) | (card X))
then A40:
rng ((Sgm0 (X \/ Y)) | (card X)) = { v where v is Element of X \/ Y : ex k2 being Nat st
( v = ((Sgm0 (X \/ Y)) | (card X)) . k2 & k2 in card X ) }
by A3, XBOOLE_0:def 10;
A50n:
now assume B1:
( not
{ v where v is Element of X \/ Y : ex k2 being Nat st
( v = ((Sgm0 (X \/ Y)) | (card X)) . k2 & k2 in card X ) } c= X & not
X c= { v where v is Element of X \/ Y : ex k2 being Nat st
( v = ((Sgm0 (X \/ Y)) | (card X)) . k2 & k2 in card X ) } )
;
:: thesis: contradictionthen consider v1 being
set such that B2:
(
v1 in { v where v is Element of X \/ Y : ex k2 being Nat st
( v = ((Sgm0 (X \/ Y)) | (card X)) . k2 & k2 in card X ) } & not
v1 in X )
by TARSKI:def 3;
consider v2 being
set such that B3:
(
v2 in X & not
v2 in { v where v is Element of X \/ Y : ex k2 being Nat st
( v = ((Sgm0 (X \/ Y)) | (card X)) . k2 & k2 in card X ) } )
by B1, TARSKI:def 3;
consider v10 being
Element of
X \/ Y such that B4:
(
v1 = v10 & ex
k2 being
Nat st
(
v10 = ((Sgm0 (X \/ Y)) | (card X)) . k2 &
k2 in card X ) )
by B2;
B98:
v10 in Y
by A20, B2, B4, XBOOLE_0:def 3;
consider k20 being
Nat such that B4b:
(
v10 = ((Sgm0 (X \/ Y)) | (card X)) . k20 &
k20 in card X )
by B4;
reconsider nv10 =
v10 as
Nat ;
X c= X \/ Y
by XBOOLE_1:7;
then consider x2 being
set such that B5:
(
x2 in dom (Sgm0 (X \/ Y)) &
v2 = (Sgm0 (X \/ Y)) . x2 )
by B3, A30, FUNCT_1:def 5;
reconsider x20 =
x2 as
Nat by B5;
reconsider nv2 =
v2 as
Nat by B5;
then B61:
len ((Sgm0 (X \/ Y)) | (card X)) <= x20
by TH80, A22;
k20 < len ((Sgm0 (X \/ Y)) | (card X))
by B4b, A4, NAT_1:45;
then B62:
k20 < x20
by B61, XXREAL_0:2;
B44:
((Sgm0 (X \/ Y)) | (card X)) . k20 = (Sgm0 (X \/ Y)) . k20
by Th19, A22, B4b;
x20 < len (Sgm0 (X \/ Y))
by B5, NAT_1:45;
then
nv10 < nv2
by B4b, B5, AC113, B62, B44;
hence
contradiction
by AE100, A1, B3, B98;
:: thesis: verum end;
(Sgm0 (X \/ Y)) | (card X) is one-to-one
by FUNCT_1:84;
then A51:
dom ((Sgm0 (X \/ Y)) | (card X)),((Sgm0 (X \/ Y)) | (card X)) .: (dom ((Sgm0 (X \/ Y)) | (card X))) are_equipotent
by CARD_1:60;
((Sgm0 (X \/ Y)) | (card X)) .: (dom ((Sgm0 (X \/ Y)) | (card X))) = rng ((Sgm0 (X \/ Y)) | (card X))
by RELAT_1:146;
then ak:
card { v where v is Element of X \/ Y : ex k2 being Nat st
( v = ((Sgm0 (X \/ Y)) | (card X)) . k2 & k2 in card X ) } = card (len ((Sgm0 (X \/ Y)) | (card X)))
by A40, A51, CARD_1:21;
then A53:
card { v where v is Element of X \/ Y : ex k2 being Nat st
( v = ((Sgm0 (X \/ Y)) | (card X)) . k2 & k2 in card X ) } = card X
by TH80, A22;
then
X,{ v where v is Element of X \/ Y : ex k2 being Nat st
( v = ((Sgm0 (X \/ Y)) | (card X)) . k2 & k2 in card X ) } are_equipotent
by CARD_1:21;
then reconsider Z0 = { v where v is Element of X \/ Y : ex k2 being Nat st
( v = ((Sgm0 (X \/ Y)) | (card X)) . k2 & k2 in card X ) } as finite set by CARD_1:68;
((Sgm0 (X \/ Y)) | (card X)) . i = (Sgm0 (X \/ Y)) . i
by Th19, A22, A1;
hence
(Sgm0 (X \/ Y)) . i in X
by A77n, A40, A1, A4, FUNCT_1:def 5; :: thesis: verum