let AP be AffinPlane; :: thesis: ( AP is Pappian implies AP is satisfying_pap )
assume A1:
AP is Pappian
; :: thesis: AP is satisfying_pap
thus
AP is satisfying_pap
:: thesis: verumproof
let M be
Subset of
AP;
:: according to AFF_2:def 13 :: thesis: for N being Subset of AP
for a, b, c, a', b', c' being Element of AP st M is being_line & N is being_line & a in M & b in M & c in M & M // N & M <> N & a' in N & b' in N & c' in N & a,b' // b,a' & b,c' // c,b' holds
a,c' // c,a'let N be
Subset of
AP;
:: thesis: for a, b, c, a', b', c' being Element of AP st M is being_line & N is being_line & a in M & b in M & c in M & M // N & M <> N & a' in N & b' in N & c' in N & a,b' // b,a' & b,c' // c,b' holds
a,c' // c,a'let a,
b,
c,
a',
b',
c' be
Element of
AP;
:: thesis: ( M is being_line & N is being_line & a in M & b in M & c in M & M // N & M <> N & a' in N & b' in N & c' in N & a,b' // b,a' & b,c' // c,b' implies a,c' // c,a' )
assume A2:
(
M is
being_line &
N is
being_line &
a in M &
b in M &
c in M &
M // N &
M <> N &
a' in N &
b' in N &
c' in N &
a,
b' // b,
a' &
b,
c' // c,
b' )
;
:: thesis: a,c' // c,a'
assume A3:
not
a,
c' // c,
a'
;
:: thesis: contradiction
A4:
(
a <> b' &
c <> b' &
b <> c' &
b <> a' &
a <> c' )
by A2, AFF_1:59;
A5:
(
a <> b &
a <> c &
b <> c )
proof
A8:
now assume A9:
a = c
;
:: thesis: contradictionthen
b,
c' // b,
a'
by A2, A4, AFF_1:14;
then
LIN b,
c',
a'
by AFF_1:def 1;
then
LIN a',
c',
b
by AFF_1:15;
then
(
a' = c' or
b in N )
by A2, AFF_1:39;
hence
contradiction
by A2, A3, A9, AFF_1:11, AFF_1:59;
:: thesis: verum end;
hence
(
a <> b &
a <> c &
b <> c )
by A6, A8;
:: thesis: verum
end;
A11:
(
a' <> b' &
a' <> c' &
b' <> c' )
proof
A12:
now assume
a' = b'
;
:: thesis: contradictionthen
a',
a // a',
b
by A2, AFF_1:13;
then
LIN a',
a,
b
by AFF_1:def 1;
then
LIN a,
b,
a'
by AFF_1:15;
then
a' in M
by A2, A5, AFF_1:39;
hence
contradiction
by A2, AFF_1:59;
:: thesis: verum end;
A13:
now assume
a' = c'
;
:: thesis: contradictionthen
a,
b' // c,
b'
by A2, A4, AFF_1:14;
then
b',
a // b',
c
by AFF_1:13;
then
LIN b',
a,
c
by AFF_1:def 1;
then
LIN a,
c,
b'
by AFF_1:15;
then
b' in M
by A2, A5, AFF_1:39;
hence
contradiction
by A2, AFF_1:59;
:: thesis: verum end;
now assume
b' = c'
;
:: thesis: contradictionthen
b',
b // b',
c
by A2, AFF_1:13;
then
LIN b',
b,
c
by AFF_1:def 1;
then
LIN b,
c,
b'
by AFF_1:15;
then
b' in M
by A2, A5, AFF_1:39;
hence
contradiction
by A2, AFF_1:59;
:: thesis: verum end;
hence
(
a' <> b' &
a' <> c' &
b' <> c' )
by A12, A13;
:: thesis: verum
end;
set K =
Line a,
c';
set C =
Line c,
b';
A14:
(
Line a,
c' is
being_line &
Line c,
b' is
being_line &
a in Line a,
c' &
c' in Line a,
c' &
c in Line c,
b' &
b' in Line c,
b' )
by A4, AFF_1:38;
then consider T being
Subset of
AP such that A15:
(
a' in T &
Line a,
c' // T )
by AFF_1:63;
A16:
(
T is
being_line &
T // Line a,
c' )
by A15, AFF_1:50;
not
Line c,
b' // T
proof
assume
Line c,
b' // T
;
:: thesis: contradiction
then
Line c,
b' // Line a,
c'
by A15, AFF_1:58;
then
c,
b' // a,
c'
by A14, AFF_1:53;
then
b,
c' // a,
c'
by A2, A4, AFF_1:14;
then
c',
b // c',
a
by AFF_1:13;
then
LIN c',
b,
a
by AFF_1:def 1;
then
LIN a,
b,
c'
by AFF_1:15;
then
c' in M
by A2, A5, AFF_1:39;
hence
contradiction
by A2, AFF_1:59;
:: thesis: verum
end;
then consider x being
Element of
AP such that A17:
(
x in Line c,
b' &
x in T )
by A14, A16, AFF_1:72;
A18:
a,
c' // x,
a'
by A14, A15, A17, AFF_1:53;
A19:
x <> b
set D =
Line x,
b;
A20:
(
Line x,
b is
being_line &
x in Line x,
b &
b in Line x,
b )
by A19, AFF_1:38;
not
Line x,
b // N
proof
assume
Line x,
b // N
;
:: thesis: contradiction
then
Line x,
b // M
by A2, AFF_1:58;
then
x in M
by A2, A20, AFF_1:59;
then
(
c in T or
b' in M )
by A2, A14, A17, AFF_1:30;
hence
contradiction
by A2, A3, A14, A15, AFF_1:53, AFF_1:59;
:: thesis: verum
end;
then consider o being
Element of
AP such that A21:
(
o in Line x,
b &
o in N )
by A2, A20, AFF_1:72;
A22:
b,
c' // x,
b'
proof
LIN b',
c,
x
by A14, A17, AFF_1:33;
then
b',
c // b',
x
by AFF_1:def 1;
then
c,
b' // x,
b'
by AFF_1:13;
hence
b,
c' // x,
b'
by A2, A4, AFF_1:14;
:: thesis: verum
end;
A23:
a' <> x
proof
assume
a' = x
;
:: thesis: contradiction
then
c,
b' // a',
b'
by A2, A4, A22, AFF_1:14;
then
b',
a' // b',
c
by AFF_1:13;
then
LIN b',
a',
c
by AFF_1:def 1;
then
c in N
by A2, A11, AFF_1:39;
hence
contradiction
by A2, AFF_1:59;
:: thesis: verum
end;
A24:
b' <> x
proof
assume
b' = x
;
:: thesis: contradiction
then
a,
c' // a',
b'
by A14, A15, A17, AFF_1:53;
then
a,
c' // N
by A2, A11, AFF_1:41;
then
c',
a // N
by AFF_1:48;
then
a in N
by A2, AFF_1:37;
hence
contradiction
by A2, AFF_1:59;
:: thesis: verum
end;
not
a,
b' // Line x,
b
proof
assume
a,
b' // Line x,
b
;
:: thesis: contradiction
then
b,
a' // Line x,
b
by A2, A4, AFF_1:46;
then
a' in Line x,
b
by A20, AFF_1:37;
then
b in T
by A15, A16, A17, A20, A23, AFF_1:30;
then
b,
a' // a,
c'
by A14, A15, AFF_1:53;
then
a,
b' // a,
c'
by A2, A4, AFF_1:14;
then
LIN a,
b',
c'
by AFF_1:def 1;
then
LIN b',
c',
a
by AFF_1:15;
then
a in N
by A2, A11, AFF_1:39;
hence
contradiction
by A2, AFF_1:59;
:: thesis: verum
end;
then consider y being
Element of
AP such that A25:
(
y in Line x,
b &
LIN a,
b',
y )
by A20, AFF_1:73;
A26:
y,
b' // b,
a'
proof
LIN b',
a,
y
by A25, AFF_1:15;
then
b',
a // b',
y
by AFF_1:def 1;
then
a,
b' // y,
b'
by AFF_1:13;
hence
y,
b' // b,
a'
by A2, A4, AFF_1:14;
:: thesis: verum
end;
A27:
Line x,
b <> N
by A2, A20, AFF_1:59;
A28:
(
o <> b' &
o <> c' &
o <> a' )
proof
A29:
now assume
o = b'
;
:: thesis: contradictionthen
LIN b',
x,
b
by A20, A21, AFF_1:33;
then
b',
x // b',
b
by AFF_1:def 1;
then
x,
b' // b,
b'
by AFF_1:13;
then
b,
c' // b,
b'
by A22, A24, AFF_1:14;
then
LIN b,
c',
b'
by AFF_1:def 1;
then
LIN b',
c',
b
by AFF_1:15;
then
b in N
by A2, A11, AFF_1:39;
hence
contradiction
by A2, AFF_1:59;
:: thesis: verum end;
A30:
now assume
o = a'
;
:: thesis: contradictionthen
LIN a',
b,
x
by A20, A21, AFF_1:33;
then
a',
b // a',
x
by AFF_1:def 1;
then
b,
a' // x,
a'
by AFF_1:13;
then
a,
b' // x,
a'
by A2, A4, AFF_1:14;
then
a,
b' // a,
c'
by A18, A23, AFF_1:14;
then
LIN a,
b',
c'
by AFF_1:def 1;
then
LIN b',
c',
a
by AFF_1:15;
then
a in N
by A2, A11, AFF_1:39;
hence
contradiction
by A2, AFF_1:59;
:: thesis: verum end;
now assume
o = c'
;
:: thesis: contradictionthen
Line x,
b // Line c,
b'
by A2, A4, A14, A20, A21, AFF_1:52;
then
b in Line c,
b'
by A17, A20, AFF_1:59;
then
LIN c,
b,
b'
by A14, AFF_1:33;
then
b' in M
by A2, A5, AFF_1:39;
hence
contradiction
by A2, AFF_1:59;
:: thesis: verum end;
hence
(
o <> b' &
o <> c' &
o <> a' )
by A29, A30;
:: thesis: verum
end;
(
o <> b &
o <> x &
o <> y )
proof
A31:
now assume
o = x
;
:: thesis: contradictionthen
N = T
by A2, A15, A16, A17, A21, A23, AFF_1:30;
then
N = Line a,
c'
by A2, A14, A15, AFF_1:59;
hence
contradiction
by A2, A14, AFF_1:59;
:: thesis: verum end;
now assume
o = y
;
:: thesis: contradictionthen
(
LIN b',
o,
a &
LIN b',
o,
a' &
LIN b',
o,
b' )
by A2, A21, A25, AFF_1:15, AFF_1:33;
then
a in N
by A2, A11, A28, AFF_1:17, AFF_1:39;
hence
contradiction
by A2, AFF_1:59;
:: thesis: verum end;
hence
(
o <> b &
o <> x &
o <> y )
by A2, A21, A31, AFF_1:59;
:: thesis: verum
end;
then
y,
c' // x,
a'
by A1, A2, A20, A21, A22, A25, A26, A27, A28, Def2;
then
y,
c' // a,
c'
by A18, A23, AFF_1:14;
then
c',
y // c',
a
by AFF_1:13;
then
LIN c',
y,
a
by AFF_1:def 1;
then
(
LIN a,
y,
c' &
LIN a,
y,
b' &
LIN a,
y,
a )
by A25, AFF_1:15, AFF_1:16;
then
(
a in Line x,
b or
a in N )
by A2, A11, A25, AFF_1:17, AFF_1:39;
then
Line x,
b // N
by A2, A5, A20, AFF_1:30, AFF_1:59;
hence
contradiction
by A21, A27, AFF_1:59;
:: thesis: verum
end;