let f be s.c.c. FinSequence of (TOP-REAL 2); :: thesis: for n being Element of NAT st n < len f holds
f | n is s.n.c.
let n be Element of NAT ; :: thesis: ( n < len f implies f | n is s.n.c. )
assume A1:
n < len f
; :: thesis: f | n is s.n.c.
let i, j be Nat; :: according to TOPREAL1:def 9 :: thesis: ( j <= i + 1 or LSeg (f | n),i misses LSeg (f | n),j )
assume A2:
i + 1 < j
; :: thesis: LSeg (f | n),i misses LSeg (f | n),j
A3:
len (f | n) <= n
by FINSEQ_5:19;
A4:
( i in NAT & j in NAT )
by ORDINAL1:def 13;
per cases
( n < j + 1 or len (f | n) < j + 1 or ( j + 1 <= n & j + 1 <= len (f | n) ) )
;
suppose that A5:
j + 1
<= n
and A6:
j + 1
<= len (f | n)
;
:: thesis: LSeg (f | n),i misses LSeg (f | n),j
j + 1
< len f
by A1, A5, XXREAL_0:2;
then A7:
LSeg f,
i misses LSeg f,
j
by A2, A4, GOBOARD5:def 4;
A8:
LSeg f,
j = LSeg (f | n),
j
by A6, SPPOL_2:3;
j <= j + 1
by NAT_1:11;
then
i + 1
<= j + 1
by A2, XXREAL_0:2;
hence
LSeg (f | n),
i misses LSeg (f | n),
j
by A6, A7, A8, SPPOL_2:3, XXREAL_0:2;
:: thesis: verum end; end;