let Omega be non empty set ; :: thesis: for Sigma being SigmaField of Omega
for P being Probability of Sigma
for F being Function of NAT , COM Sigma,P ex BSeq being SetSequence of Sigma st
for n being Element of NAT holds BSeq . n in ProbPart (F . n)
let Sigma be SigmaField of Omega; :: thesis: for P being Probability of Sigma
for F being Function of NAT , COM Sigma,P ex BSeq being SetSequence of Sigma st
for n being Element of NAT holds BSeq . n in ProbPart (F . n)
let P be Probability of Sigma; :: thesis: for F being Function of NAT , COM Sigma,P ex BSeq being SetSequence of Sigma st
for n being Element of NAT holds BSeq . n in ProbPart (F . n)
let F be Function of NAT , COM Sigma,P; :: thesis: ex BSeq being SetSequence of Sigma st
for n being Element of NAT holds BSeq . n in ProbPart (F . n)
defpred S1[ Element of NAT , set ] means for n being Element of NAT
for y being set st n = $1 & y = $2 holds
y in ProbPart (F . n);
A1:
for t being Element of NAT ex A being Element of Sigma st S1[t,A]
ex G being Function of NAT ,Sigma st
for t being Element of NAT holds S1[t,G . t]
from FUNCT_2:sch 3(A1);
then consider G being Function of NAT ,Sigma such that
A2:
for t, n being Element of NAT
for y being set st n = t & y = G . t holds
y in ProbPart (F . n)
;
for n being Nat holds G . n in Sigma
then A3:
rng G c= Sigma
by NAT_1:53;
reconsider BSeq = G as SetSequence of Omega by FUNCT_2:9;
reconsider BSeq = BSeq as SetSequence of Sigma by A3, PROB_1:def 9;
take
BSeq
; :: thesis: for n being Element of NAT holds BSeq . n in ProbPart (F . n)
thus
for n being Element of NAT holds BSeq . n in ProbPart (F . n)
by A2; :: thesis: verum