let A be closed-interval Subset of REAL ; :: thesis: integral (sin * (AffineMap 2,0 )),A = (((- (1 / 2)) (#) (cos * (AffineMap 2,0 ))) . (sup A)) - (((- (1 / 2)) (#) (cos * (AffineMap 2,0 ))) . (inf A))
A1:
[#] REAL = dom (sin * (AffineMap 2,0 ))
by FUNCT_2:def 1;
A2:
[#] REAL = dom (AffineMap 2,0 )
by FUNCT_2:def 1;
for x being Real st x in REAL holds
(AffineMap 2,0 ) . x = (2 * x) + 0
by JORDAN16:def 3;
then
(AffineMap 2,0 ) | REAL is continuous
by A2, FDIFF_1:31, FDIFF_1:33;
then A3:
(AffineMap 2,0 ) | A is continuous
by FCONT_1:17;
B1:
sin | REAL is continuous
by SIN_COS:73, FDIFF_1:33;
sin | ((AffineMap 2,0 ) .: A) is continuous
by B1, FCONT_1:17;
then
(sin * (AffineMap 2,0 )) | A is continuous
by A3, FCONT_1:26;
then A4:
( sin * (AffineMap 2,0 ) is_integrable_on A & (sin * (AffineMap 2,0 )) | A is bounded )
by A1, INTEGRA5:10, INTEGRA5:11;
A5:
for x being Real st x in REAL holds
(AffineMap 2,0 ) . x = 2 * x
A6:
(- (1 / 2)) (#) (cos * (AffineMap 2,0 )) is_differentiable_on REAL
by Lm3, A5, FDIFF_6:38;
A7:
for x being Real st x in dom (((- (1 / 2)) (#) (cos * (AffineMap 2,0 ))) `| REAL ) holds
(((- (1 / 2)) (#) (cos * (AffineMap 2,0 ))) `| REAL ) . x = (sin * (AffineMap 2,0 )) . x
proof
let x be
Real;
:: thesis: ( x in dom (((- (1 / 2)) (#) (cos * (AffineMap 2,0 ))) `| REAL ) implies (((- (1 / 2)) (#) (cos * (AffineMap 2,0 ))) `| REAL ) . x = (sin * (AffineMap 2,0 )) . x )
assume
x in dom (((- (1 / 2)) (#) (cos * (AffineMap 2,0 ))) `| REAL )
;
:: thesis: (((- (1 / 2)) (#) (cos * (AffineMap 2,0 ))) `| REAL ) . x = (sin * (AffineMap 2,0 )) . x
(((- (1 / 2)) (#) (cos * (AffineMap 2,0 ))) `| REAL ) . x =
sin (2 * x)
by Lm3, A5, FDIFF_6:38
.=
sin . ((AffineMap 2,0 ) . x)
by A5
.=
(sin * (AffineMap 2,0 )) . x
by A1, FUNCT_1:22
;
hence
(((- (1 / 2)) (#) (cos * (AffineMap 2,0 ))) `| REAL ) . x = (sin * (AffineMap 2,0 )) . x
;
:: thesis: verum
end;
dom (((- (1 / 2)) (#) (cos * (AffineMap 2,0 ))) `| REAL ) = dom (sin * (AffineMap 2,0 ))
by A1, A6, FDIFF_1:def 8;
then
((- (1 / 2)) (#) (cos * (AffineMap 2,0 ))) `| REAL = sin * (AffineMap 2,0 )
by A7, PARTFUN1:34;
hence
integral (sin * (AffineMap 2,0 )),A = (((- (1 / 2)) (#) (cos * (AffineMap 2,0 ))) . (sup A)) - (((- (1 / 2)) (#) (cos * (AffineMap 2,0 ))) . (inf A))
by Lm3, A4, A5, FDIFF_6:38, INTEGRA5:13; :: thesis: verum