let A be non empty closed_interval Subset of REAL; for f being PartFunc of REAL,REAL
for Z being open Subset of REAL st A c= Z & f = cos / exp_R & Z c= dom ((1 / 2) (#) ((sin - cos) / exp_R)) & Z = dom f & f | A is continuous holds
integral (f,A) = (((1 / 2) (#) ((sin - cos) / exp_R)) . (upper_bound A)) - (((1 / 2) (#) ((sin - cos) / exp_R)) . (lower_bound A))
let f be PartFunc of REAL,REAL; for Z being open Subset of REAL st A c= Z & f = cos / exp_R & Z c= dom ((1 / 2) (#) ((sin - cos) / exp_R)) & Z = dom f & f | A is continuous holds
integral (f,A) = (((1 / 2) (#) ((sin - cos) / exp_R)) . (upper_bound A)) - (((1 / 2) (#) ((sin - cos) / exp_R)) . (lower_bound A))
let Z be open Subset of REAL; ( A c= Z & f = cos / exp_R & Z c= dom ((1 / 2) (#) ((sin - cos) / exp_R)) & Z = dom f & f | A is continuous implies integral (f,A) = (((1 / 2) (#) ((sin - cos) / exp_R)) . (upper_bound A)) - (((1 / 2) (#) ((sin - cos) / exp_R)) . (lower_bound A)) )
assume A1:
( A c= Z & f = cos / exp_R & Z c= dom ((1 / 2) (#) ((sin - cos) / exp_R)) & Z = dom f & f | A is continuous )
; integral (f,A) = (((1 / 2) (#) ((sin - cos) / exp_R)) . (upper_bound A)) - (((1 / 2) (#) ((sin - cos) / exp_R)) . (lower_bound A))
then A2:
( f is_integrable_on A & f | A is bounded )
by INTEGRA5:10, INTEGRA5:11;
A3:
(1 / 2) (#) ((sin - cos) / exp_R) is_differentiable_on Z
by A1, Th9;
A4:
for x being Real st x in Z holds
f . x = (cos . x) / (exp_R . x)
by A1, RFUNCT_1:def 1;
A5:
for x being Element of REAL st x in dom (((1 / 2) (#) ((sin - cos) / exp_R)) `| Z) holds
(((1 / 2) (#) ((sin - cos) / exp_R)) `| Z) . x = f . x
dom (((1 / 2) (#) ((sin - cos) / exp_R)) `| Z) = dom f
by A1, A3, FDIFF_1:def 7;
then
((1 / 2) (#) ((sin - cos) / exp_R)) `| Z = f
by A5, PARTFUN1:5;
hence
integral (f,A) = (((1 / 2) (#) ((sin - cos) / exp_R)) . (upper_bound A)) - (((1 / 2) (#) ((sin - cos) / exp_R)) . (lower_bound A))
by A1, A2, Th9, INTEGRA5:13; verum