let IT1, IT2 be odd Element of NAT ; :: thesis: ( ( v in W .vertices() & IT1 <= len W & W . IT1 = v & ( for n being odd Nat st n <= len W & W . n = v holds
IT1 <= n ) & IT2 <= len W & W . IT2 = v & ( for n being odd Nat st n <= len W & W . n = v holds
IT2 <= n ) implies IT1 = IT2 ) & ( not v in W .vertices() & IT1 = len W & IT2 = len W implies IT1 = IT2 ) )

hereby :: thesis: ( not v in W .vertices() & IT1 = len W & IT2 = len W implies IT1 = IT2 )
assume v in W .vertices() ; :: thesis: ( IT1 <= len W & W . IT1 = v & ( for n being odd Nat st n <= len W & W . n = v holds
IT1 <= n ) & IT2 <= len W & W . IT2 = v & ( for n being odd Nat st n <= len W & W . n = v holds
IT2 <= n ) implies IT1 = IT2 )

assume that
A10: IT1 <= len W and
A11: W . IT1 = v and
A12: for n being odd Nat st n <= len W & W . n = v holds
IT1 <= n ; :: thesis: ( IT2 <= len W & W . IT2 = v & ( for n being odd Nat st n <= len W & W . n = v holds
IT2 <= n ) implies IT1 = IT2 )

assume that
A13: IT2 <= len W and
A14: W . IT2 = v and
A15: for n being odd Nat st n <= len W & W . n = v holds
IT2 <= n ; :: thesis: IT1 = IT2
A16: IT2 <= IT1 by ;
IT1 <= IT2 by ;
hence IT1 = IT2 by ; :: thesis: verum
end;
assume not v in W .vertices() ; :: thesis: ( not IT1 = len W or not IT2 = len W or IT1 = IT2 )
thus ( not IT1 = len W or not IT2 = len W or IT1 = IT2 ) ; :: thesis: verum